Without an equality sign the given expression can't be considered to be an equation.
Without an equality sign the given terms can't be considered to be an equation of a straight line.
Substitute the x coordinate into the equation for x and calculate y. If the formla gives the same y value as the coordinates, the point is on the line. If it is diffent, it is not on the line.
79
(5, -8)
A line is represented by an equation. Each solution of the equation is a point on the line, and each point on the line is a solution to the equation. So the line is just the graph of the solution set of the equation.
A point lies on a line if the coordinates of the point satisfy the equation of the line.
Without an equality sign it can not be considered to be an equation
(6,2)
Without an equality sign the given terms can't be considered to be an equation of a straight line.
That of course would depend on the straight line equation that has not been given and so therefore an answer is not possible.
Substitute the x coordinate into the equation for x and calculate y. If the formla gives the same y value as the coordinates, the point is on the line. If it is diffent, it is not on the line.
A number of point lies on it...................(-2,-44), (-1,-19),(0,6), (1,31), (2, 56)...............
79
To determine if a point is on a line, you can use the equation of the line. For example, if the line is represented by the equation (y = mx + b) (slope-intercept form), substitute the x-coordinate of the point into the equation to see if the resulting y-value matches the point's y-coordinate. If they match, the point lies on the line; if not, it does not. Alternatively, you can use other forms of the line equation, such as standard form, to perform a similar check.
To determine which point lies on the line described by the equation ( y + 4 = 4x - 3 ), we first simplify the equation to ( y = 4x - 7 ). Then, we can test specific points by substituting their coordinates into this equation to see if they satisfy it. For instance, if we test the point (2, 1), substituting ( x = 2 ) gives ( y = 4(2) - 7 = 1 ), confirming that (2, 1) lies on the line.
(5, -8)
If it is a straight line, then the equation is linear.