(6,2)
A number of point lies on it...................(-2,-44), (-1,-19),(0,6), (1,31), (2, 56)...............
the slope of a line is 9/5 the y intercept is -4, express the equation of the line in point slope form
(y - y1) = m*(x - x1) where (x1, y1) are the coordinates of a point on the line and , is the slope.
Point: (1, 4) Slope: -3 Equation: y = -3x+7
Slope: -3 Point: (4, -5) Equation: y = -3x+7
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Without an equality sign the given terms can't be considered to be an equation of a straight line.
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
Without an equality sign the given expression can't be considered to be an equation.
A number of point lies on it...................(-2,-44), (-1,-19),(0,6), (1,31), (2, 56)...............
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
That will depend on the value of the slope which has not been given.
A point lies on a line if the coordinates of the point satisfy the equation of the line.
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
The point-slope form of a line's equation is given by (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is a point on the line. Given the slope (m = -5) and the point ((1, -1)), the equation in point-slope form is (y + 1 = -5(x - 1)).
The slope of a curved line at a point is the slope of the tangent to the curve at that point. If you know the equation of the curve and the curve is well behaved, you can find the derivative of the equation of the curve. The value of the derivative, at the point in question, is the slope of the curved line at that point.