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Suppose the equation ax^2 + bx + c = 0 has the discriminant d.Then the solutions to the quadratic are:
x1 = [-b - sqrt(d)]/2a and x2 = [-b + sqrt(d)]/2a
If d > 0 then sqrt(d) is some real non-zero number.
Sqrt(d) is real implies x1 and x2 are real.
sqrt(d) is non-zero implies that x1 and x2 are distinct.
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How many solutions will a problem have if the discriminant is positive?
Two real roots.
How many real solutions does a quadratic function have when the value of its discriminant is seven?
If the discriminant is positive, as in this case, there are two real solutions.Also: * If the discriminant is zero, there is one real solution, considered to be a "double solution" because of the way polynomials are factored. * If the discriminant is negative, there are two complex solutions, which are complex and non-real.
If the discriminant of a quadratic equation is -4 how many solutions does the equation have?
If the discriminant of a quadratic equation is less then 0 then it will have no real solutions.
Why are there usually two solutions in quadratic equations and when do they only have one solution?
If the discriminant of the quadratic equation is greater than zero then it will have two different solutions. If the discriminant is equal to zero then it will have two equal solutions. If the discriminant is less than zero then it will have no real solutions.
How do you know if a quadratic equation will have more than one solutions?
Write the quadratic equation in the standard form: ax2 + bx + c = 0 Then calculate the discriminant = b2 - 4ac If the discriminant is greater than zero, there are two distinct real solutions. If the discriminant is zero, there is one real solution. If the discriminany is less than zero, there are no real solutions (there will be two distinct imaginary solutions).
