You most likely your node numbers mixed up somewhere, double check them.
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A singular matrix is one that has a determinant of zero, and it has no inverse. Global stiffness can mean rigid motion of the body.
The singular form of matrices is matrix.
A singular matrix is a matrix which has no inverse because its determinant is zero. If you recall, the inverse of a matrix is1/ ad-bc multiplied by:[ d -b ][-c a ]If ad-bc = 0, then the inverse matrix would not exist because 1/0 is undefined, and hence it would be a singular matrix.E.g.[ 1 3][ 2 6]Is a singular matrix because 6x1-3x2 = 0.
When the matrix of coefficients is singular.
Let A by an nxn non-singular matrix, then A-1 is the inverse of A. Now (A-1 )-1 =A So the answer is yes.