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y = 3x + 2 y-2 = 3x x = (y-2)/3 So the inverse is (x-2)/3
21-7y+3x-xy7(3-y)+x(3-y)
y = 3x 3x + 4y = 30 3x + 4(3x) = 30 3x + 12x = 30 15x = 30 x = 2 y = 3x y = 3(2) y = 6 (2, 6)
f(x) = 3x + 9 y = 3x + 9 so 3x = y - 9 x = y/3 - 3 Therefore, the inverse function is g(x) = x/3 - 3
y=3x+3 -- This could be the formula for a line, where the slope is 3 and the y intercept is (0,3). In the next line the slope would be 4 and the y-intercept would be 5
3x+7x+3+y= 10x+3+y
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
y = 3x + 6slope = 3
one is y=3x+3 so is y=3x+5
y=3x+4 -3x+y=4 x=-1/3
3x + 3 (y-z)
If you mean y = 2/3x +3 then it is a straight line equation whereas 2/3 is the slope and 3 is the y intercept
y = 3x + 2 y-2 = 3x x = (y-2)/3 So the inverse is (x-2)/3
y=2 + 3x seems like a linear equation, therefore, y=3x + 2.The gradient is 3.
For the equation y = 3x + 3, the value of m (the slope) is 3.
If: 3x+y = 16 Then: y = -3x+16 whereas -3 is the slope and 16 is the y intercept
Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7