We need to get both equations into slope-intercept form. If they are parallel, they will have the same slope. If they are perpendicular, they will have slopes that when multiplied equal -1. (unless one line is horizontal and the other vertical) 3x+2y=5 2y=5-3x y=(-3/2)x+(5/2) 3x+2y=9 2y=9-3x y=(-3/2)x+(9/2) The two lines are parallel, since both slopes are equal to (-3/2).
y=-2/3x with any y-intercept except -2.
Given point: (6, 7) Equation: 3x+y = 8 Parallel equation: 3x+y = 25
Since the two lines are parallel, then they have the same slope, 3. Thus, the equation of the line with y-intercept -4, and parallel to y = 3x - 3 is y = 3x - 4.
Rewriting the equation 3x + y = 15 gives y = 15 - 3xThe slope of this and any parallel line is the x multiple, which in this case is -3
The lines are parallel.
Their graphs are.
They are perpendicular lines because the slopes are 3/4 and -4/3 respectively.
They are parallel straight lines,
parallel
There are an infinite number of lines that are all parallel to [ y = 3x + 6 ].Here are ten of them to get you started:y = 3x - 1y = 3xy = 3x + 1y = 3x + 2y = 3x + 3y = 3x + 4y = 3x + 5y = 3x + 5.99y = 3x + 6.001y = 3x + 7.etc.
y=2/(3x) + 2 isn't linear so nonthing can be parallel to it as "parallel" can only apply to lines.
17
6
No. they are parallel, since the slopes are both equal in this case 3. To be perpendicular the product of the slopes of both lines is equal to -1 (i.e., m1*m2 = -1).
No, the two lines are not perpendicular.
y=3x+b where b≠6 is any real number.