this is very hard to write out without superscripts so it would be written out like this:
y= k times x times cubed root of z
if this was all reduced it would be:
y=kx(z^1/3 )
i think this is right. >_<
i hope this helped!
Chat with our AI personalities
One step you usually want to take is to move any perfect square out of the radical. Example 1, with numbers: root(12) = root(4x3) = root(4) x root(3) = 2 root(3) Example 2, with variables: root(y cubed) = root(y squared times y) = root(y squared) times root(y) = y root(y)
135
Divide both sides of the equation by Y2.That will leave you with X / Y2 = Y* * * * *That doesn't quite do it, does it? Try this:Take the cube root of both sides.y = ³√x.
Joint variation is a variation in which y varies jointly as x or powers of x () and y or powers of z ( ), if there is some nonzero constant k such that , where x ≠ 0, z ≠ 0, and n > 0. Source~http://www.icoachmath.com/SiteMap/JointVariation.html
y^3 + y^2 - 6 (y+2) (y-3) i think