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It is x^2 + xy + y^2

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Q: What is the solution when x cubed -y cubed is divided by x -y?
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What is 4x cubed y cubed z divided by x negative squared y negative 1 z sqaured?

4x cubed y cubed z divided by x negative squared y negative 1 z sqaured = 4


Six x squared divided by y times y cubed divided by twelve x to the fourth?

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How do you factor 64 x cubed minus y cubed?

64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)


X cubed plus y cubed equal 25?

This has infinitely many solutions. The idea is to solve the equation for one of the variables, say for "y". The solution will be in terms of "x" in this case. Then, if you assign any value to "x", you can calculate the corresponding value for "y".


How do you factor x cubed plus y cubed?

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What is 1 divided by x divided by 2 divided by y?

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What is a number divided by a minus number?

X divided by -Y is the same as -X divided by Y. Or - (X/Y)


What is the solution to x divided by 5 y divided by 3?

1.6667


Can every ratio be written as the ratio of some number to 1?

Given X:Y, where X and Y are the integers of your ratio, divide both sides by Y. Then you'll have: (X / Y) : (Y / Y) Recognizing that an integer divided by itself is equal to one, (Y / Y) = 1 Finally, you are left with your solution of (X / Y) : 1 Given X:Y, where X and Y are the integers of your ratio, divide both sides by Y. Then you'll have: (X / Y) : (Y / Y) Recognizing that an integer divided by itself is equal to one, (Y / Y) = 1 Finally, you are left with your solution of (X / Y) : 1


What is x cubed divided by y squared?

You can only get a specific number for an expression if you assign numbers to the variables. As an expression, the existing expression cannot be simplified.


What is x minus 1 cubed?

xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1