1 to 6 or u can write it as 1:6
[]Digital touch ups []Makeup []Pins [x]All of the above
The Bubble Model.
layered model architecture is tcp/ip model .you can reference this model as layered model architecture protocol.
Mossberg Model 340.
Remington never made the Model 4 in 270 Winchester.
Fg
the scale factor for a model is 5 cm + _________ m
The size of the actual car would be 25 times 9 inches. That comes to 225 inches. To get the answer in feet, divide by 12. That would make the actual car 18.75 feet (18 feet, 9 inches).
To find the scale factor, divide the height of the basketball player by the height of the model. The player is 6 feet 8 inches tall, which is equivalent to 80 inches (6 feet x 12 inches/foot + 8 inches). The model is 5 inches tall, so the scale factor is 80 inches / 5 inches = 16. Therefore, the scale factor is 16:1.
To find the wingspan of Raul's scale model, divide the actual wingspan of 44 feet by the scale factor of 116116. Calculating this gives approximately 0.000379 feet, which is about 0.00455 inches, a very small model size.
The scale in this case is roughly 1 to 3.21 You don't mention if the 5 cm is model or actual, but if the 5 is model, the actual is 16.05. If the 5 is actual, the model is 1.56 I'm assuming all measurements are in centimeters, but you didn't mention that either.
81 feet by 153 feet
all you have to do is have to figure out from which of the shapes your starting with. So if you decide to start with a scale factor from the larger figure to the smaller figure all u do is the opposite. You do the small divided my the large. So if u want it from the small shape to the large shape scale factor you do the large divided by the small.
To find the area of the actual playground, you need to square the scale factor of 3, which equals 9. Then, multiply the area of the scale model (6 square yards) by this squared scale factor to get the area of the actual playground. Therefore, the area of the actual playground is 6 square yards multiplied by 9, which equals 54 square yards.
To find the actual length of the train, we can set up a proportion based on the scale. The model train is 35 inches long, and according to the scale, 7 inches corresponds to 90 feet. Therefore, we can calculate the actual length as follows: [ \text{Actual Length} = \left( \frac{90 , \text{feet}}{7 , \text{inches}} \right) \times 35 , \text{inches} = 450 , \text{feet}. ] Thus, the actual length of the train is 450 feet.
1450ft
study a system you cannot see directly