Nothing, particularly. a could be 0 and multiplication is commutative.
Here is a proof. Let a and b be any two real numbers. Consider the number x defined as x = ab + (-a)(b) + (-a)(-b). We can write this out differently as x = ab + (-a)[ (b) + (-b) ] Then, by factoring out -a , we find that x= ab + (-a)(0) = ab + 0 = ab. Also, x = [ a + (-a) ]b + (-a)(-b) And by factoring out b, we find that x=0 * b + (-a)(-b) = 0 + (-a)(-b) = (-a)(-b). Therefore x = ab and x = (-a)(-b) Then, by the transitivity of equality, we have ab = (-a)(-b).
If your asking about the value of "X" it can equal to any number of real numbers. But at the end any number of X multiplied by 000 will equal to 0, ; , .-'"""'-. , ; , \\|/ .' '. \|// \-;-/ () () \-;-/ // ; ; \\ //__; :. .; ;__\\ `-----\'.'-.....-'.'/-----' '.'.-.-,_.'.' '( (..-' '-'
In binary this would be written as 1011. This is because in binary (from right to left) the digits in this number mean: (1 * 20) + (1 * 21) + (0 * 22) + (1 * 23). This, of course, is equal to (1 * 1) + (1 * 2) + (0 * 4) + (1 * 8), which equals 1 + 2 + 0 + 8, which equals 11 (in decimal).
4
zero is rational because it can be written as a fraction where the denominator is not equal to 0. it can be written as 0/1, 0/2, 0/3, etc
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
ab=1a+1b a is equal to either 0 or two, and b is equal to a
Do you mean "What is -10 to the power 0 equal to?" Any number raised to 0 evaluates to 1
Any number to the power of 0 is always equal to 1
Assuming that cross means 'divide' B is equal to 0
If you mean to ask what number results in the same answer when divided by either 4 or 6, the only number that works is zero. 0/4 = 0/6 = 0
the number 0 is always equal to its opposite
There are many intuitive explanations that show it works. For example, you can look at debt as a negative number or you can use the number line to see why negative times negative is a positive. None of these is really a proof. In fact, since any negative number is really the same positive number multiplied by -1, i.e. -5=5x-1 when we really need to ask only why is -1x-1=1. One good, but often not satisfying, answer is that if we use any other convention, then it won't work. The fact is, it is a convention. For the mathematical purist, here is a nice proof that two negatives multiplied together equal a positive Let a and b be any two real numbers. Consider the number n defined by n = ab + (-a)(b) + (-a)(-b). We can write n= ab + (-a)[ (b) + (-b) ] if we just actor out -a = ab + (-a)(0) = ab + 0 = ab. Also, n = [ a + (-a) ]b + (-a)(-b) if we factor out b = 0 * b + (-a)(-b) = 0 + (-a)(-b) = (-a)(-b). So we have n = ab and n = (-a)(-b) Hence, by the transitivity of equality, we have ab = (-a)(-b) and the proof is complete.
x-ab=0 x=ab
-2a^2
Here is a proof. Let a and b be any two real numbers. Consider the number x defined as x = ab + (-a)(b) + (-a)(-b). We can write this out differently as x = ab + (-a)[ (b) + (-b) ] Then, by factoring out -a , we find that x= ab + (-a)(0) = ab + 0 = ab. Also, x = [ a + (-a) ]b + (-a)(-b) And by factoring out b, we find that x=0 * b + (-a)(-b) = 0 + (-a)(-b) = (-a)(-b). Therefore x = ab and x = (-a)(-b) Then, by the transitivity of equality, we have ab = (-a)(-b).
I assume that by a mixed number you mean a number of the form ab/c where a is an integer greater than 0 (otherwise the number would be a simple fraction), the answer is No.