2x2 + 17x - 9 = 2x2 + 18x - x - 9 = 2x(x + 9) - 1(x + 9) = (2x - 1)(x + 9)
(2x + 7)(x - 2)
(2x + 1)(x + 3) are the factors.
Doesn't factor evenly, use quadratic
7x(3x3 - 2x2 + 5x + 1)
You would first factor out anything that is common between the 3 parts. 2x2 is the greatest common factor. To pull out the 2x2, you divide each term by 2x2 like so:12x4/2x2=6x210x3/2x2=5x-12x2/2x2=-6We now know that 12x4+10x3-12x2= 2x2(6x2+5x-6)The next step involves using the "slip and slide" method for the trinomial inside the parentheses:6x2+5x-6x2+5x-36(x+9)(x-4)(x+9/6)(x-4/6)(x+3/2)(x-2/3)(2x+3)(3x-2)Remembering that the result for the slip and slide method only accounts for 6x2+5x-6 we must multiply (2x+3)(3x-2) by 2x2.Your final answer is 2x2(2x+3)(3x-2).
(2x + 7)(x - 2)
2x2 + 15x + 25 = (2x + 5)(x + 5)
A Quadratic statement
(2x+7)(x+7)
(2x + 1)(x + 3) are the factors.
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
2x2 + 21x + 49 = 2x2 +14x +7x + 49 = 2x(x + 7) + 7(x + 7) = (2x + 7)(x + 7)
2x2+21x+49 = (2x+7)(x+7)
Presumably all the terms are positive? (2x+7(x+7)
(2x + 1) (x + 3) = 2x2 + 7x + 3
2x2+9x+9 = (2x+3)(x+3) when factored
2x2+13x+15 = (2x+3)(x+5)