(2x + 7)(x - 2)
(2x + 1)(x + 3) are the factors.
Doesn't factor evenly, use quadratic
7x(3x3 - 2x2 + 5x + 1)
If that's 2x2, the answer is (x + 2)(x2 + 4)
(2x + 7)(x - 2)
2x2 + 15x + 25 = (2x + 5)(x + 5)
A Quadratic statement
(2x+7)(x+7)
(2x + 1)(x + 3) are the factors.
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
2x2 + 21x + 49 = 2x2 +14x +7x + 49 = 2x(x + 7) + 7(x + 7) = (2x + 7)(x + 7)
2x2+21x+49 = (2x+7)(x+7)
Presumably all the terms are positive? (2x+7(x+7)
(2x + 1) (x + 3) = 2x2 + 7x + 3
2x2+9x+9 = (2x+3)(x+3) when factored
2x2+13x+15 = (2x+3)(x+5)