answersLogoWhite

0


Best Answer

If z = a + ib

then

arg(z) = arctan(b/a)

Let z' denote the conjugate of z. Therefore, z' = a - ib

Then

arg(z') = arctan(-b/a) = 2*pi - arctan(b/a) = 2*pi - arg(z)

User Avatar

Wiki User

9y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: If z equals a plus ib then show that arg conjugate of z equals 2pi -arg z?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Basic Math

2pi is an integer?

2 times pi is not an integer. Since Pi is an irrational number, 2 pi is also an irrational number.


Will the sum of two irrational numbers always be rational?

Consider pi and 4 - pi. 4 - pi + pi = 4, which is clearly rational. However, both pi and 4 - pi are irrational, as you can verify. plz to be lerning numburs Then consider pi + pi = 2pi, which is clearly irrational. The sum of two irrational numbers, therefore, may or may not be rational.


Find the square root of a complex number system?

Probably the best way is to change the complex number to its polar form, [or the A*eiΘ form] A is the magnitude or the distance from the origin to the point iin the complex plane, and Θ is the angle (in radians) measured counterclockwise from the positive real axis to the point. To find the square root of a number in this form, take the positive square root of the magnitude, then divide the angle by 2. Since there will always be 2 square roots for every number, to find the second root, add 2pi radians to the original angle, then divide by 2. Take an easy example of square root of 4. Which we know is 2 and -2. OK so the magnitude is 4 and the angle is 0 radians. zero divided by 2 is zero, and the positive square root of 4 is 2. Now for the other square root. Add 2pi radians to 0, which is 2pi, then divide by 2, which is pi. pi radians [same as 180°] points in the negative real direction (on the horizontal), so we have ei*pi = -1 and then multiply by sqrt(4) = -2. Try square root of i. i points straight up (pi/2 radians) with magnitude of 1. So the magnitude of the square root is still 1, but it points at pi/4 radians (45°). Converting back to rectangular gives you sqrt(2)/2 + i*sqrt(2)/2. The other square root will always point in the opposite direction [180° or pi radians]. So the other square root is at 225° or 5pi/4 radians, and the rectangular for this is -sqrt(2)/2 - i*sqrt(2)/2. Using FOIL (from Algebra) you can multiply it out like two binomials and you will get i when you square either of the two answers for square root.


Is the sum of 2 irrational numbers rational?

No. The irrational parts may cancel out.For example, 1 + sqrt(2) and 5 - sqrt(2) are both irrational but their sum is 1 + 5 = 6.


What is the POLAR form of complex numbers?

By creating a real-imaginary plane (real on horizontal axis, imaginary on vertical), any complex number can be represented graphically. The polar form is a magnitude and angle. The magnitude is measured from the origin to the point on the plane. For a complex number a + bi, this value is a2 + b2. The angle is measured from the positive real axis, clockwise. For positive imaginary part (b), this will be +arccos(a/(a2 + b2)). (0° to +180°, or 0 to +pi radians) For negative imaginary part (b), this will be -arccos(a/(a2 + b2)). (0° to -180°, or 0 to -pi radians, or alternatively 180° to 360° or pi to 2pi radians)