tn = n2 - n + 3
It is 75
420/115 = 84/23 84 = 23 + 23 + 23 + 15 3 and 15/23
15 is composite number 17, 19 and 23 are prime numbers.
The pattern is +5, +6, +7, so the next number will be 23 + 8 or 31.
14
15!
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
58
It is: 27-2n
Assuming this is a linear or arithmetic sequence, the nth term is Un = 31 - 8n. But, there are infinitely many polynomials of order 5 or higher, and many other functions that will fit the above 5 numbers.
5, 11, 17, 23, 29
We note that the numbers rise by addition of ;7;7 between terms. Hence we can write 7n . The first term( n- 1) is '9' So we can write 7(1) + c = 9 7 + c = 9 c = 2 So the nth term becomes 7n + 2
the equation that defines this sequence is nx = (n+(7+4(x-1))) (where x is the position of the term in the sequence (that is position 1 is 12, position 2 is 23 etc..)
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The nth term is 3(n+1). The twenty-third term is equal to 3 x (23 + 1) = 72
It is 4n -1 and so the next term will be 23