(2a + 10)(2a - 12)
Assuming the missing signs are pluses, that factors to (4a + 3)(a + 3)
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
2a
4(4a2 - b2) 4(2a + b)(2a - b)
The greatest common factor (GCF) of 4a and 10a is 2a. To find the GCF, we need to identify the largest factor that both 4a and 10a have in common. In this case, both 4a and 10a can be divided by 2 and a, making 2a the greatest common factor.
(4a - 1)(a - 4)
Assuming the missing signs are pluses, that factors to (4a + 3)(a + 3)
4a3 - 4a2 = 4a2*(a - 1)
4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)
x2=(4a)(a) x=√4a2 x=2a The geometric mean of a and 4a is 2a
4a^2 - 25 can be factored as (2a + 5)(2a - 5) using the difference of squares formula, where a is a variable.
= 4a2 + 2ab 2b2
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
(2a + 1)(2a - 5)
There are two answers in the solution set. To solve this we factor the left side to become 4a(a-4). This lets us get the 4. The other answers is 0. Set 4a=0 and solve for "a" and then a-4=0 and solve for "a."
2a
sqrt(4a2) = 21plus or minus (2a) = 21plus or minus (a) = 10.5a = +10.5a = -10.5