(2a + 10)(2a - 12)
Assuming the missing signs are pluses, that factors to (4a + 3)(a + 3)
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
2a
4(4a2 - b2) 4(2a + b)(2a - b)
Oh, dude, the Greatest Common Factor (GCF) of 4a and 10a is 2a. It's like the cool kid that both 4a and 10a can hang out with without any drama. So, if 4a and 10a were at a party, 2a would be the one they both vibe with.
(4a - 1)(a - 4)
Assuming the missing signs are pluses, that factors to (4a + 3)(a + 3)
4a3 - 4a2 = 4a2*(a - 1)
4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)
x2=(4a)(a) x=√4a2 x=2a The geometric mean of a and 4a is 2a
4a^2 - 25 can be factored as (2a + 5)(2a - 5) using the difference of squares formula, where a is a variable.
= 4a2 + 2ab 2b2
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
(2a + 1)(2a - 5)
There are two answers in the solution set. To solve this we factor the left side to become 4a(a-4). This lets us get the 4. The other answers is 0. Set 4a=0 and solve for "a" and then a-4=0 and solve for "a."
2a
The expression "4a2 3ab" seems to be a combination of terms, but it looks like it may be missing an operator between "4a2" and "3ab." If you meant to add them, it would be written as 4a² + 3ab, which represents a polynomial with two terms. The first term, 4a², has a coefficient of 4 and a degree of 2 in variable 'a', while the second term, 3ab, has a coefficient of 3 and includes both variables 'a' and 'b'. If you meant something else, please clarify!