Assuming the missing signs are pluses, that factors to (4a + 3)(a + 3)
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
2a
4(4a2 - b2) 4(2a + b)(2a - b)
The greatest common factor (GCF) of 4a and 10a is 2a. To find the GCF, we need to identify the largest factor that both 4a and 10a have in common. In this case, both 4a and 10a can be divided by 2 and a, making 2a the greatest common factor.
(4a - 1)(a - 4)
Assuming the missing signs are pluses, that factors to (4a + 3)(a + 3)
4a3 - 4a2 = 4a2*(a - 1)
4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)
x2=(4a)(a) x=√4a2 x=2a The geometric mean of a and 4a is 2a
4a^2 - 25 can be factored as (2a + 5)(2a - 5) using the difference of squares formula, where a is a variable.
= 4a2 + 2ab 2b2
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
(2a + 1)(2a - 5)
It is 4a2.
The given equation is 4a^2 - 16a = 0. Factoring out a common factor of 4a, we get 4a(a - 4) = 0. This equation is satisfied when either 4a = 0 or (a - 4) = 0. Solving these, we find that the solution set is a = 0 and a = 4.
2a