Factor 4a2 - 25 is (2a+5)(2a-5).
There are two answers in the solution set. To solve this we factor the left side to become 4a(a-4). This lets us get the 4. The other answers is 0. Set 4a=0 and solve for "a" and then a-4=0 and solve for "a."
No, it would be an abiotic factor.
nothing it depends on what factor was removed
The primary determing factor would be the size of the substance
Well, if you're talking about the growth factor for the exponential problems, you can simply convert the percent of the growth rate and add 1. Eg. Growth Rate = 25%, Growth Factor will equal to 1.25 because 25% = 0.25. 0.25 plus 1 is equal to 1.25. Eg. Growth Rate = 5%, Growth Factor will equal to 1.05 because 5% = 0.05. 0.05 plus one is equal to 1.05. Hope that's what you want =)
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
(2a + 1)(2a - 5)
2a
(4a - 1)(a - 4)
(2a + 10)(2a - 12)
Assuming the missing signs are pluses, that factors to (4a + 3)(a + 3)
4a2
4a2 + 4ab - y2 + b2 You cannot simplify this expression because it does not contain like terms, but you can factor it such as: 4a2 + 4ab - y2 + b2 = (4a2 + 4ab + b2) - y2 = (2a + b)2 - y2 = [(2a + b) - y][(2a + b) + y]
(2a + c)(4a2 - 2ac + c2)
4(4a2 - b2) 4(2a + b)(2a - b)
12a4 + 16a64a4(3 + 4a2)=========
That factors to 4(a - b)(a + 3b)