5a times 3a minus 8a = (5*3)*a2 - 8a = 15a2 - 8a
4
8a+48b=
8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.
9a - 8a = a
4x2-8x-5 (2x+1)(2x-5)
4a^2 - 25 can be factored as (2a + 5)(2a - 5) using the difference of squares formula, where a is a variable.
(2a + 1)(4a2 - 2a + 1)
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
8a + 1 is in its simplest form and does not factor.
2a
(4a - 1)(a - 4)
8a(5a2-1)
(2a + 10)(2a - 12)
4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)
No.
Assuming the missing signs are pluses, that factors to (4a + 3)(a + 3)