If that was - 10x + 21, it would factor to (x - 3)(x - 7) If that was + 10x + 21, it would factor to (x + 3)(x + 7) As it is, the solutions are irrational.
x2 + 10x + 25 --> (x + 5)2
(x + 2)(x - 12)
Given: x2 + 10x - 16 Let: x2 + 10x - 16 = 0 x2 + 10x - 16 = 0 ∴ x2 + 10x + 25 = 16 + 25 ∴ (x + 5)2 = 41 ∴ x = -5 ± √41 ∴ x2 + 10x - 16 = (x + 5 + √41)(x + 5 - √41)
If that's -10x - 39, the answer is (x - 13)(x + 3) If that's +10x - 39, the answer is (x + 13)(x - 3)
If that was - 10x + 21, it would factor to (x - 3)(x - 7) If that was + 10x + 21, it would factor to (x + 3)(x + 7) As it is, the solutions are irrational.
x2+10x+21 = (x+3)(x+7)
x2+10x-336
x2 + 10x + 21 = (x + 3)(x + 7)
x2 + 10x + 25 --> (x + 5)2
(x2+10x+21)/(x+3) = (x+7)
x2+10x+21 = (x+3)(x+7) when factored.....
Doesn't factor evenly
x2+10x-24 = (x-2)(x+12)
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.
That expression can not be factored.
(x + 2)(x - 12)