x2 + 10x + 25 --> (x + 5)2
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Given: x2 + 10x - 16 Let: x2 + 10x - 16 = 0 x2 + 10x - 16 = 0 ∴ x2 + 10x + 25 = 16 + 25 ∴ (x + 5)2 = 41 ∴ x = -5 ± √41 ∴ x2 + 10x - 16 = (x + 5 + √41)(x + 5 - √41)
If that's + 10x + 21, the answer is (x + 7)(x + 3)
If the missing signs are pluses, that factors to (x + 5)(x + 5) or (x + 5)2
If that was - 10x + 21, it would factor to (x - 3)(x - 7) If that was + 10x + 21, it would factor to (x + 3)(x + 7) As it is, the solutions are irrational.
(x + 2)(x - 12)