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How do you factor x squared minus y squared?
The factoring is as follows: x2 - y2 = (x + y) * (x - y)
How do you factor 2x2-xy-3y2?
(2x - 3y)(x + y)
How do you factor x3 plus y3?
(x2 - xy + y2)(x + y)
What is the greatest common factor of x2y xy2?
To find the greatest common factor of x^2y and xy^2, we need to determine the highest power of each variable that is common to both terms. In this case, the common factors are x and y. The highest power of x that is common to both terms is x^1, and the highest power of y that is common to both terms is y^1. Therefore, the greatest common factor of x^2y and xy^2 is xy.
How do you factor xy x?
Oh, what a happy little question! To factor out xy from xy, you simply take out the common factor, which is xy itself. So, the factored form of xy is just xy. Isn't that just lovely? Just remember, there are no mistakes in math, only happy little accidents.
How do you factor xy squared-x?
x(y - 1)(y + 1)
What is the GCF of x squared y and xy squared?
The GCF is xy
Factor X squared y plus axy plus abx plus a squared b?
x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
How do you factor x squared plus xy?
Divide by 'x'; x2+xy/x = x(x+y)
How do you factor x squared plus 8x-xy-8y?
0
Factor 2x squared plus 2x plus xy plus y?
4
How do you factor x squared -8x plus xy-8y?
-16
What is xy cubed z squared plus y squared z plus xyz completely factorised?
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
How do you factor xy x?
Oh, what a happy little question! To factor out xy from xy, you simply take out the common factor, which is xy itself. So, the factored form of xy is just xy. Isn't that just lovely? Just remember, there are no mistakes in math, only happy little accidents.
What is Xy divided by y squared?
It is then x/y when simplified
How do you factor x-y plus xy-1?
(x-y) + (xy - 1) = (x - 1)(y + 1)
Factor x squared y - xyb - abx plus ab squared?
Factor by grouping. x2y - xyb - abx + ab2 The first two can factor out an xy, so xy(x - b) The second two can factor out a -ab, so -ab(x - b) and we have xy(x - b) - ab(x - b) Since what is inside the parentheses is alike, we can be assured that we have factored correctly and now continue to group: ANS: (x - b)(xy - ab)
