That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (5 plus or minus the square root of 73) divided by 12.
y = 1.128666978776461
y = -0.2953336454431275
Remember both 16 & 25 are squared numbers. 16 = 4^2 & 25 = 5^2 Hence we can write (4x)^2 - (5y)^2 Remember two squared terms with a NEGATIVE Between them will factor. ( 4x - 5y)(4x + 5y) Note the difference signs. NNB Two squared terms with a positive (+) between them DOES NOT factor.
2(x - 5y)
5(3x + 2 + y)
(y + 8)(y - 2)
No
12y3 - 30y2 + 12yFactor out a y:y(12y2 - 30y + 12)Factor out a 6:6y(2y2 -5y + 2)Factor 2y2 - 5y + 26y(2y - 1)(y - 2)
(5y - 2)(5y + 2)
Remember both 16 & 25 are squared numbers. 16 = 4^2 & 25 = 5^2 Hence we can write (4x)^2 - (5y)^2 Remember two squared terms with a NEGATIVE Between them will factor. ( 4x - 5y)(4x + 5y) Note the difference signs. NNB Two squared terms with a positive (+) between them DOES NOT factor.
6 - y + 5y - 6y = 0 6 = y -5y + 6y 6 = -4y + 6y 6 = 2y 6/2 = y 3 = y
2y^2+5y+2=(2y+1)(y+2)
Pull out the common factor of 2 ... 2(y^2+6y-16) Then just factor (y^2+6y-16) ... (y-2)(y+8)
(13x^2 - 4y)(2x^2 - 5y)
2
5y - 2 + y + 52 = 6y + 50 - 3y6y + 50 = 9y + 50y = 0
6y + 2 = y + 17 => 5y = 15 => y = 3
5y - 2 = 28 - y 5y + y = 28 + 2 6y = 30 y = 30/6 y = 5
This is a special kind of expression called a difference of squares. Anything in the format a2 - b2 can be factored out as (a + b)(a - b). So we can say: x2 - 25y2 = x2 - (5y)2 = (x + 5y)(x - 5y)