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What is the point-slope form of a line with slope -3 that contains the point (10-1)?
The point-slope form of a line is given by the equation ( y - y_1 = m(x - x_1) ), where ( m ) is the slope and ( (x_1, y_1) ) is a point on the line. Given a slope of -3 and the point (10, -1), we can substitute these values into the formula: ( y - (-1) = -3(x - 10) ). This simplifies to ( y + 1 = -3(x - 10) ), or ( y + 1 = -3x + 30 ). Thus, the point-slope form is ( y + 1 = -3(x - 10) ).
What is the slope intercept form of the equation for the line that passes through the point (-10-6) and has a slope of -1?
The slope-intercept form of a line is given by the equation ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope ( m = -1 ) and a point (-10, -6), we can substitute these values into the equation to find ( b ): [ -6 = -1(-10) + b \implies -6 = 10 + b \implies b = -16. ] Thus, the slope-intercept form of the line is ( y = -x - 16 ).
What is the point-slope equation of the line with slope -10 that goes through the point (14)?
If you mean point of (1, 4) and slope of -10 then y = -10x+14
What is the point-slope equation of the line with slope -10 that goes through the point (1 4)?
If you mean point of (1, 4) and slope of -10 then y = -10x+14
What is the slpoe in 4x plus 5y equals -10?
Put in point slope form. Y =mX + c 4X + 5Y = - 10 5Y = - 4X - 10 Y = - (4/5)X - 2 =========== The slope(m) = - 4/5 --------------------------
Write in point slope form the equation of a line that has a slope of -3 and passes through point (2 4) use y-y1m(x-x1)?
Point: (2, 4) Slope: -3 Equation: y = -3x+10
What is the point-slope form of a line with slope -3 that contains the point (10-1)?
The point-slope form of a line is given by the equation ( y - y_1 = m(x - x_1) ), where ( m ) is the slope and ( (x_1, y_1) ) is a point on the line. Given a slope of -3 and the point (10, -1), we can substitute these values into the formula: ( y - (-1) = -3(x - 10) ). This simplifies to ( y + 1 = -3(x - 10) ), or ( y + 1 = -3x + 30 ). Thus, the point-slope form is ( y + 1 = -3(x - 10) ).
What is the slope intercept form of the equation for the line that passes through the point (-10-6) and has a slope of -1?
The slope-intercept form of a line is given by the equation ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope ( m = -1 ) and a point (-10, -6), we can substitute these values into the equation to find ( b ): [ -6 = -1(-10) + b \implies -6 = 10 + b \implies b = -16. ] Thus, the slope-intercept form of the line is ( y = -x - 16 ).
What is the slope if the line 4X plus 2Yequals 10?
Need point slope form. Y = mX + c 4X + 2Y = 10 2Y = - 4X + 10 Y = - 2X + 5 ========= slope(m) = - 2 -------------------
What is the point-slope equation of the line with slope -10 that goes through the point (14)?
If you mean point of (1, 4) and slope of -10 then y = -10x+14
What is the the equation of the line that passes through -3 4 with a slope of 2 in point slope form?
Point: (-3, 4) Slope: 2 Equation: y-4 = 2(x--3) => y = 2x+10
What is the point-slope equation of the line with slope -10 that goes through the point (1 4)?
If you mean point of (1, 4) and slope of -10 then y = -10x+14
What is the point slope equation of the line with slope -10 that goes through the point(14)?
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
What is the point slope equation of the line with slope -10 that goes through the point (14)?
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
What is equation point slope form contains the points 8 10 and -4 2?
Points: (8, 10) and (-4, 2) Slope: 2/3 Equation: 3y = 2x+14
What 2 pieces of information must you have to write a linear equation in slope intercept form?
You will need to find the slope and the y-intercept. For example: find the equation of the line containing points (0,5) and (2,10) and write it in slope-intercept form. The slope (m) here is found using the formula (y2-y1)/(x2-x1) So... (10-5)/(2-0) = 5/2 The y-intercept (b) is the value of y at the point where x=0 So... it is 5 The slope-intercept formula is y=mx+b So... that gives us y=(5/2)x+5
What is the point-slope equation of the line with slope -10 that goes through the point 14?
It is: y = -10x+14
