Points: (-10, 3) and (-2, -5)
Slope: -1
Equation: y = -x-7
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If you mean point of (1, 4) and slope of -10 then y = -10x+14
Put in point slope form. Y =mX + c 4X + 5Y = - 10 5Y = - 4X - 10 Y = - (4/5)X - 2 =========== The slope(m) = - 4/5 --------------------------
y= -4x + 10 Slope intercept form is y=mx+b
5x - 2y = 10 2y = 5x - 10 y = 2.5x - 5......which is the equation in slope intercept form.
Point: (2, 4) Slope: -3 Equation: y = -3x+10
Need point slope form. Y = mX + c 4X + 2Y = 10 2Y = - 4X + 10 Y = - 2X + 5 ========= slope(m) = - 2 -------------------
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
Point: (-3, 4) Slope: 2 Equation: y-4 = 2(x--3) => y = 2x+10
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
Points: (8, 10) and (-4, 2) Slope: 2/3 Equation: 3y = 2x+14
It is: y = -10x+14
You will need to find the slope and the y-intercept. For example: find the equation of the line containing points (0,5) and (2,10) and write it in slope-intercept form. The slope (m) here is found using the formula (y2-y1)/(x2-x1) So... (10-5)/(2-0) = 5/2 The y-intercept (b) is the value of y at the point where x=0 So... it is 5 The slope-intercept formula is y=mx+b So... that gives us y=(5/2)x+5
(4, 10); m = -1/4 y = mx + b replace y with 10, m with -1/4, and x with 4 10 = (-1/4)4 + b 10 = -1 + b add 1 to both sides 11 = b y = (-1/4)x + 11
Put in point slope form. Y =mX + c 4X + 5Y = - 10 5Y = - 4X - 10 Y = - (4/5)X - 2 =========== The slope(m) = - 4/5 --------------------------