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The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
y=3x-3
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
Point-slope form is written as: y-y1=m(x-x1), where (x1, y1) is a point on the line and m is the slope (hence the name, point-slope form).
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Point: (2, -1) Slope: -5 Equation: y = -5x+9
y-1 = 3(x - 2)
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
If you mean a point of: (2,1) then the equation works out as y = 3x-5
y = 2x + 1
Slope: -3 Point: (4, -5) Equation: y = -3x+7
y=2x+13
y=3x-3
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
The answe iss..... 6
y = 2x - 1