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To find the point-slope form of a linear equation, you first need the equation in slope-intercept form (y = mx + b) or at least identify a point and the slope. The equation you've provided, "4x y 10," seems incomplete or unclear. If you mean (4x + y = 10), you can rearrange it to (y = -4x + 10), giving a slope (m = -4). The point-slope form is then (y - y_1 = m(x - x_1)) where ((x_1, y_1)) is any point on the line, such as (0, 10).
To graph the equation (2x - 4y = 8), first, rearrange it into slope-intercept form (y = mx + b). Start by isolating (y): (4y = 2x - 8) simplifies to (y = \frac{1}{2}x - 2). This equation shows a slope of (\frac{1}{2}) and a y-intercept at (-2). Plot the y-intercept on the graph, then use the slope to find another point by rising 1 unit and running 2 units to the right, and draw the line through these points.
To find the intercepts of a quadratic equation in the standard form ( y = ax^2 + bx + c ), the y-intercept can be found by evaluating the equation at ( x = 0 ), which gives the point ( (0, c) ). For the x-intercepts, set ( y = 0 ) and solve the equation ( ax^2 + bx + c = 0 ) using the quadratic formula ( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). The resulting values of ( x ) will give the x-intercepts.
If you define the rise and run in terms of the coordinates of two points on the line whose slope you are trying to find, then you should see that the two are exactly the same.
It is not possible to answer the question since no equation is given in the question: only an expression.
the slope formula is y=mx+b slope-intercept form of an equation of a line. where m=slope and b=the y-intercept
the formula for slope-intercept form is y=mx+b. in the equation mx is the slope and b is the y-intercept.
y = {slope}x + {y intercept}
A normal slope-intercept form equation would read: y = mx + b The slope of an equation is also known as 'm'. The y-intercept would count as 'b'. So in a random equation such as: y= 5x + 6 '5' would be the slope and '6' would be the y-intercept.
The slope intercept form is y=mx+b where m is the slope and b is the y intercept y=2x-8.
Since your equation is already in slope-intercept form, it's easy. Slope-intercept form is as follows: y=mx+b m always ends up being your slope, and b is your y intercept. Slope = 5, and the y intercept = 8 in your equation.
y=-4
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
The slope intercept form equation is stated as the following: y= mx + b. Where m is the slope or the coefficient in front of the x and b is the y intercept.
A vertical line on a graph has infinite slope and no y-intercept. Its equation is [ x = a number ]. The number is the line's x-intercept.
y = 2x + b to find y-intercept, you should know one point. you put the point into x and y. and you can find y-intercept. if you are still confused, i want you to follow the related link that explains the concept of slope intercept form very clearly.
Use: (y2 -y1)/(x2 -x1) to find the slope. Use: y -y1 = m(x -x1) to find the slope intercept equation whereas m is the slope.