"IT IS ALWAYS A ODD"
No. Sum of odd + odd = even Sum of odd + even = odd Sum of even + even = even
All odd numbers are of the form 2n + 1, where n is an integer.So an odd number minus an odd number is (2n+1) - (2m+1) = 2n -2m = 2(n-m). Both n and m are integers, so while we don't know whether n-m is odd or even, we definitely know that it's an integer and that multiplying it by two cannot possibly give an odd number. So an odd number minus an odd number is an even number. For similar reasons, an odd number plus an odd number is also an even number.
an odd numberSubtracting an odd number from an even number will always result in an odd number.
Your question is incomplete. Adding an even number with an odd number will always result in an odd number. Multiplying an even number with an odd number will always result in an even number.
Other than the number 2, all other prime numbers are odd. As 469 is odd then it must be formed by the addition of an even number (2) and an odd number (467). The two prime numbers are thus 2 and 467.
Assuming you know that your number is a perfect square, the square root of an even number is even, and the square root of an odd number is odd.
Odd, shouldn't you know that?
Even I know it's even !
If its not divisible by 2 evenly then it is an odd number.
odd * odd = odd answer even * even = even answer odd * even = even answer
I don't know lol
Yes. The final digit is a two... always look at the last digit in a number if you want to know whether it is even or odd. if the number is even, the whole number is even and if the last digit is odd than the whole number is odd.
"IT IS ALWAYS A ODD"
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2.
All even numbers are between odd numbers and so 0 is between -1 and 1 which makes it an even number.
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.