12n > 36 n > 3
8+2n
As an algebraic expression it is: 2x-9
2n+12=x
2.4 < 2.45 < 2.5
12n > 36 n > 3
5n > 25
r <= 5.
2x + 2 > x + 5
Let the number be x and so: 2x+3 > 49
Twice a number would be written as 2x.
It is: 8 > Y > -2
x ≥ -4
2z
To write this algebraically: 2x+18>25 and solve: 2x>25-18 x>7/2 Therefore x (a number) must be greater than 7/2.
To write out the given statement algebraically, you would start by defining the variable for the number, let's say it is represented by 'x'. The equation would be: 6x - 5 < 2x + 10. This equation represents the statement "Six times a number minus five is less than twice the number plus ten" in algebraic form. To solve this inequality, you would isolate the variable 'x' by performing operations to simplify and find the range of values that satisfy the inequality.
To write twice the sum of a number and 600, you first express the number as a variable, such as ( x ). The sum of the number and 600 can be written as ( x + 600 ). Therefore, twice this sum is represented as ( 2(x + 600) ).