6. 957, 975, 597, 579, 795, 759.
There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.
2250
Only one positive prime number has a 5 in the ones digit. That prime number is 5. All other numbers with a 5 in the ones digit are composite because they will be divisible by 5.
1, 2, 3, 4, 5, 6, 7, 8 and 9 are all 1 digit whole numbers
The answer depends on what the tens digit is greater than, and what the ones digit does then.
None. 3 digit numbers are not divisible by 19 digit numbers.
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
There are 180 3-digit numbers divisible by five.
The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2. 5
6
27 three digit numbers from the digits 3, 5, 7 including repetitions.
There are 5*5*5 = 125 such numbers.
How many two digit number are divisible by 5
To determine how many digit numbers can be formed using the digits 2, 3, 5, 7, and 8, we need to consider the number of digits in the numbers we are forming. For a 1-digit number, we can use any of the 5 digits. For a 2-digit number, we can choose 2 out of the 5 digits and arrange them, giving us (5 \times 4) combinations. We can continue this for 3-digit, 4-digit, and 5-digit numbers, which will yield (5), (20), (60), and (120) respectively. Therefore, the total number of digit numbers is (5 + 20 + 60 + 120 = 205).
6 (15,30,45,60,75,90)
about... 25 just take 5 numbers times 5 numbers
There are 5*4*3 = 60 such numbers.