There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.
2250
Only one positive prime number has a 5 in the ones digit. That prime number is 5. All other numbers with a 5 in the ones digit are composite because they will be divisible by 5.
1, 2, 3, 4, 5, 6, 7, 8 and 9 are all 1 digit whole numbers
The answer depends on what the tens digit is greater than, and what the ones digit does then.
None. 3 digit numbers are not divisible by 19 digit numbers.
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
There are 180 3-digit numbers divisible by five.
The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2. 5
6
27 three digit numbers from the digits 3, 5, 7 including repetitions.
There are 5*5*5 = 125 such numbers.
How many two digit number are divisible by 5
6 (15,30,45,60,75,90)
about... 25 just take 5 numbers times 5 numbers
If a digit can be repeated there are 5 x 5 x 5 = 125 possible numbers If a digit cannot be repeated there are 5 x 4 x 3 = 60 possible numbers.
There are 5*4*3 = 60 such numbers.