04, 40
08, 80
44, 44
48, 84
88, 88
Three of them if you don't count the first two.
Its multiples will have 5 or 0 at the end of the number.
NO. All multiples of 5 have a final digit of 0 or 5. Therefore 1001 with its final digit of 1 is NOT a multiple of 5.
To find a common multiple for 2, 4, and 7 with a digit sum of 11, we first need to find the multiples of each number. The multiples of 2 are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, and so on. The multiples of 4 are 4, 8, 12, 16, 20, and so on. The multiples of 7 are 7, 14, 21, 28, 35, and so on. By examining the lists, we find that the number 28 is a common multiple for 2, 4, and 7 with a digit sum of 11.
17
All integers have an infinite amount of multiples.
90
No two digit prime number exists that is a multiple of 7. All two digit numbers that are multiples of 7 are compositenumbers.
Its multiples will have 5 or 0 at the end of the number.
Any multiple of four must be even; any number ending in three is odd. Look at the multiples of four from 1 to 9. They are in the order : 4,8,12,16,20,24,28,32,36. Now, any number when multiplied by 4, will have the one's digit as the one's digit of the above multiples In the above multiples, no multiple has 3 as the one's digit, i.e., no multiple ends in three. Take an example. 15x4 will have 0 in the one's digit because 5x4 = 20 and has 0 in the one's place.
A multiple of 50 is any number in the 50 times table. So the 3 digit multiples of 50 are: 100, 150, 200 ... 850, 900, 950.
To determine the number of 3-digit numbers that are multiples of 5, we need to find the first and last 3-digit multiples of 5. The first 3-digit multiple of 5 is 100, and the last 3-digit multiple of 5 is 995. To find the total number of such multiples, we can use the formula (Last - First) / 5 + 1 = (995 - 100) / 5 + 1 = 180. Therefore, there are 180 3-digit numbers that are multiples of 5.
a multiple is a number that is the answer of a multiplication question for example4 is a multiple of 2 becuase 2 multiplyed by 2 equals 4
The largest two-digit multiple of 5 is 95. This is because the multiples of 5 within the two-digit range start from 10 and go up to 95, with each multiple increasing by 5. The next multiple, 100, is a three-digit number, so 95 remains the largest two-digit multiple.
"If the units digit and the hundreds digit of the number 513 were reversed..." 315 'find the sum of the original number and the new number." 513+315=828
It is the integer that you get by dividing the three digit number by 10. Alternatively, the number of the multiples of ten is that you get when you truncate the rightmost number. for example assume a three digit number 517 Divide 517 by ten, you get 51.7 The integer number is 51 Alternatively, if you trnucate the rightmost number (7) you get 51 also then the answer the three digit number 517 has 51 multiples of 10.
The multiples of 10 are numbers that can be evenly divided by 10. In the case of 3-digit multiples of 10, the smallest 3-digit multiple of 10 is 100 (10 x 10), and the largest 3-digit multiple of 10 is 990 (10 x 99). Therefore, the 3-digit multiples of 10 range from 100 to 990, inclusive.
Find a four digit number whose digits will be reversed when multiplied by nine?