04, 40
08, 80
44, 44
48, 84
88, 88
Three of them if you don't count the first two.
Its multiples will have 5 or 0 at the end of the number.
NO. All multiples of 5 have a final digit of 0 or 5. Therefore 1001 with its final digit of 1 is NOT a multiple of 5.
17
All integers have an infinite amount of multiples.
999 is a three-digit multiple of 9
90
No two digit prime number exists that is a multiple of 7. All two digit numbers that are multiples of 7 are compositenumbers.
Its multiples will have 5 or 0 at the end of the number.
Any multiple of four must be even; any number ending in three is odd. Look at the multiples of four from 1 to 9. They are in the order : 4,8,12,16,20,24,28,32,36. Now, any number when multiplied by 4, will have the one's digit as the one's digit of the above multiples In the above multiples, no multiple has 3 as the one's digit, i.e., no multiple ends in three. Take an example. 15x4 will have 0 in the one's digit because 5x4 = 20 and has 0 in the one's place.
A multiple of 50 is any number in the 50 times table. So the 3 digit multiples of 50 are: 100, 150, 200 ... 850, 900, 950.
a multiple is a number that is the answer of a multiplication question for example4 is a multiple of 2 becuase 2 multiplyed by 2 equals 4
"If the units digit and the hundreds digit of the number 513 were reversed..." 315 'find the sum of the original number and the new number." 513+315=828
It is the integer that you get by dividing the three digit number by 10. Alternatively, the number of the multiples of ten is that you get when you truncate the rightmost number. for example assume a three digit number 517 Divide 517 by ten, you get 51.7 The integer number is 51 Alternatively, if you trnucate the rightmost number (7) you get 51 also then the answer the three digit number 517 has 51 multiples of 10.
Divide the two-digit number by the one-digit number. If the remainder is zero then the 2-digit number is a multiple and if not, it is not.
Find a four digit number whose digits will be reversed when multiplied by nine?
There are 2000 4-digit numbers that are multiples of 5, so, instead of listing them all, it is equally valid to say: Any4-digit number whose final digit is either a 5 or a 0 is a multiple of 5. Get Right? :P
12 is the only number which satisfies this. Multiples of 4 are: 4, 8, 12, 16, . . . .