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What is the factor of 3y squared plus 15y minus 5y minus 25?
(3y - 5)(y + 5)
Is y minus 3 a factor of y to the fourth power plus 2 y to the second power minus 4?
No.
Factor by grouping x3 - x2 plus 40x -40?
(x2 plus 40) (x minus 1)
What is the factor to 9x squared plus 12x minus 1?
That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: (-2 plus or minus the square root of 5) divided by 3x = 0.07868932583326327x = -1.4120226591665965
What is the factor x2 plus x minus 42?
(x + 7)(x - 6)
What is the factor of 3y squared plus 15y minus 5y minus 25?
(3y - 5)(y + 5)
how to factor the problem a cubed minus two a squared plus six a minus twelve?
(a - 2)(a^2 + 6)
Factor ab minus 2ac plus b squared minus 2bc?
(b-c)(a+b)-ac
How do you factor 3x squared plus 9x minus 2x minus 6?
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
How do you factor x squared minus 2x plus 2?
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: 1 plus or minus i where i is the square root of negative one.
How do you factor 2a2 plus 2a minus 84?
2(a + 7)(a - 6)
How do you factor x squared minus 5x plus 3?
There are no rational factors.
How do you factor 2x squared plus 4x minus 1?
There is no rational factorisation.
Is y minus 3 a factor of y to the fourth power plus 2 y to the second power minus 4?
No.
How do you factor 6Xcubed plus 10Xsquared minus 9X minus 20?
(3x - 4)(2x^2 + 6x + 5)
Factor 6b minus 6ac plus 6b squared minus 6bc?
6(b - ac + b2 - bc)
Factor 6ab minus 6ac plus 6b squared minus 6bc?
6(ab - ac + b2 - bc)
