56 = 2 x 28 = 4 x 14 = 7 x 8
It must have at least 3 factors.
Dividend-remainder= divisor*quotient 5694/43 give 132 quotient and 18 remainder.now 5694-18 =5676 is exactly divisible by 43. so 18 must be subracted.
No, it's not. 243 is divisible by 3 and 81. To be prime, a number's only factors must be 1 and itself.
Yes. To be composite, the first number has at least 2 prime factors, the second number also has at least prime factors; the product of the two will have at least 4 prime factors, so it must be a composite number.
9400รท65 gives144 quotient,40 remainder. 65ร145 =9425 25 is the least
1, 2, 4, 7, 14, 28
If a number is divisible by 6, then it must also be divisible by all the factors of 6, because 6 is just a multiple of each of its factors.
8.
It must have at least 3 factors.
In order for a number to be divisible by 16, the last four digits of the number must form a multiple of 16.
Subtracting 1 would do it...
For a number to be divisible by another number it must be at least that number. As 3 is less than 605 it cannot be divisible by 605. Also 3 is not a FACTOR of 605, that is 3 does not divide into 605 without remainder.
For a number to be divisible by another number it must be at least that number. As 3 is less than 837 it cannot be divisible by 837. However, 3 IS a FACTOR of 837, that is 3 divides into 837 without remainder.
100 And by the way, if 100 is a factor, that also means that the number must be divisible by 100.
Dividend-remainder= divisor*quotient 5694/43 give 132 quotient and 18 remainder.now 5694-18 =5676 is exactly divisible by 43. so 18 must be subracted.
The number 2 has only two factors: 1 and itself. Everything other even number is divisible by two, which means the number has at least three factors: 1, 2, and itself, which means they cannot be prime and must be composite.
It is 1 because 734688/3 = 244896