There isn't one. The only two digit numbers whose sum of digits is 12 are: 39, 48, 57, 66. (I didn't include 75, 84, or 93 since interchanging their digits and subtracting from the original number will be a negative result.) None of the four remaining numbers will exceed the original by 25. 66 won't work since the difference will be zero. Using 39, the new number (93) will exceed the original by 54; using 48 the difference will be 36; and using 57 the difference will be 18
-- "The sum of a two-digit number" is unclear. I took it to mean"The sum of the digits of a two-digit number."-- "... the product ?" is unclear. Are you looking for the product of the two digits,or the product of the forward and backward numbers ?-- It's not possible to write a number whose two digits sum to 12 and whosereverse exceeds it by 25. The tens digit would have to be 4.611... and the unitsdigit would have to be 7.388... .Then(4.611...) + (7.388...) = 12(46.111...) + (7.388...) = 53.5(73.888...) + (4.611...) = 78.5Difference = 25So, the number can't be written, but ...The product of its two digits is 34.071 (rounded)The product of the forward and reverse numbers is 4,199.75 (rounded)
17
105 is not a prime number. You can readily see that 3 and 5 go into it, and 7 goes into it too. The number ends in 5, and 5 goes into any number ending in 0 or 5. The sum of the digits is 6, and when the sum of the digits is divisible by 3, then so is the original number.
Yes it is... If you add the digits of ANY number together - and the result can be divided exactly by 3 or 9 - then the original number will also divide by 3 or 9. Since the digits of this number add together to make 18 - then 32643 will also divide by 3 or 9.
Integers of 6 digits are normally greater than integers of 5 digits
-- "The sum of a two-digit number" is unclear. I took it to mean"The sum of the digits of a two-digit number."-- "... the product ?" is unclear. Are you looking for the product of the two digits,or the product of the forward and backward numbers ?-- It's not possible to write a number whose two digits sum to 12 and whosereverse exceeds it by 25. The tens digit would have to be 4.611... and the unitsdigit would have to be 7.388... .Then(4.611...) + (7.388...) = 12(46.111...) + (7.388...) = 53.5(73.888...) + (4.611...) = 78.5Difference = 25So, the number can't be written, but ...The product of its two digits is 34.071 (rounded)The product of the forward and reverse numbers is 4,199.75 (rounded)
3 and 6
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
39
A) If a number has two digits, then the sum of its digits is less than the value of the original two-digit number.
whats the answer please??
Possibility of two digit no whose sum is 17 89 and 98 Reverse of 89 is 98. 98 is 9 less than the original no 89. 89 is original no
Add all the digits of the number together - if the sum of the digits is divisible by 9, then the original number is too.
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
The number is 36
38
17