x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)
(x2 + 1)(x - 3)
People wont understand if you place it in that format, the polynomial should look like x^3+4x^2+2.
x2 • (5x2 + x + 8)
x3-5x2+x is already simplified.
True.
-6. And the word is still minus, not minis.
your equation is this... x3 + 5x2 = 6x get all the terms on the left side x3 + 5x2 - 6x = 0 now factor out an "x" x(x2 + 5x - 6) = 0 now factor the equation inside x(x + 6)(x - 1) from this you can find your x-values x= 0, -6, and 1 now that you have your x-values your equation is solved. just use algebra to get all of the terms on the one side. then factor out anything that is common in all of the terms. then factor the polynomial. then find what values for "x" that satisfy the equation.
x3 - 3x2 + x - 3 = (x2 +1)( x - 3)
x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
To factorise x3 + 5x2 - 16x - 80 I note that -80 = 5 x -16 and 5 & -16 are the coefficients of x2 and x. Thus I have: x3 + 5x2 - 16x - 80 = (x + 5)(x2 - 16) and the second term is a difference of 2 squares, meaning I have: x3 + 5x2 - 16x - 80 = (x + 5)(x + 4)(x - 4)
x3 + 5x2 + 2x - 8It's a third-order polynomial in 'x'.Its value depends entirely on the value of 'x', and whenever 'x' changes,the value of the whole polynomial instantly changes.
you can factorise 5x2-24x-12 if you use the quadratic formula: This goes to (24(+/-)sqrt(816))/(10) =5.257 or -0.4566 (4s.f.)
(x - 2)(x - 2)(x - 1)
They are -1, 1 and 5.
It is a polynomial of the fourth degree in X.