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What are two consecutive even integers such that the smaller added to 3 times the larger gives a sum of 22?
Suppose n is the smaller integer. Since it is even, let n = 2x where x is an integer. Then the second integer is 2x+2 So 2x + 3*(2x+2) = 22 2x + 6x + 6 = 22 8x + 6 = 22 Subtract 6 from both sides: 8x = 16 Divide both sides by 4: 2x = 4 So the two integers are 2x and 2x+2 ie 4 and 6
Solve each equation by graphing Round to the nearest tenth x squared minus 6x equals -8?
14
36x2 plus 60x plus 25 factor completely?
(6x + 5)(6x + 5) or (6x + 5)2
How do you factor x2 6x-2?
x2 + 6x - 2 can not be factored
Three times the square of a certain positive number exceeds six times the number by nine. Find the number?
3x2 - 9 = 6x 3x2 - 6x - 9 = 0 3(x + 1)(x - 3) x = -1, 3 The answer is 3. Check it. 27 - 9 = 18 It checks.
If x is a positive integer solve x2 plus 6x equals 16?
x2 + 6x = 16x2 + 6x - 16 = 0(x + 8)(x - 2) = 0x + 8 = 0 or x - 2 = 0x = -8 or x = 2Since it is given that x > 0, then x = -8 is not a solution of the equation. Thus, the only solution is x = 2.
How do you solve for -16 equals 6x?
-16 = 6x Swap: 6x = -16 Divide both sides by 6: x = -16/6 = -8/3 or -22/3 or -2.66...
How can you solve the problem one positive integer is 3 greater than anotherthe sum of the squares of the two integers is 89find the integers?
Let one positive integer be x, so the other is x+3. The sum of the squares of the two integers is 89, so we have:x2 + (x+3)2 = 89x2 + (x2+6x+9) = 892x2 + 6x + 9 = 892x2 + 6x +9 - 89 = 02x2 + 6x - 80 = 0x2 + 3x - 40 = 0(X+8)(x-5)=0x = 5 (the only positive integer)The 2 positive integers are 5 & 8. Squaring both would be 25 & 64, which the sum is 89.
How do you solve 9 plus 6x equals 25-2x?
9+6x = 25-2x 6x+2x = 25-9 8x = 16 x = 2
Solve for 6x-4x-2?
-6x, -4x =
How do you solve -20 equals -4x-6x?
-4x-6x = -20 -10x = -20 Divide both sides by -10 rembering that a minus divided into a minus the result is positive: x = 2
What is the answer to the equation -10 equals 6x - 16?
-10 = 6x - 16, or 16 - 10 = 6x, or x = 1.
Find all degree solutions 2sin2 6x plus 3sin6x plus 1 equals 0?
2sin2(6x) + 3sin(6x) + 1 = 0 Solving the quadratic, sin(6x) = -1 or sin (6x) = -0.5 sin(6x) = -1 => 6x = 45+60n degrees for integer n sin(6x) = -0.5 => 6x = 35+60n or 55+60n degrees for integer n.
How do you solve 6x-5 equals 7?
6x-5 = 7, 6x = 7+5, 6x = 12, x = 2
How do you solve -6x - 2 -6x?
The given expression can be simplified to -12x-2
How do you solve x2 6x 27?
please help on this x2+6x+27=
How do you solve 40 equals 4-6x?
40=4-6x 40-(4)=4-6x-(4) 36=-6x -6=x
