x2 + 6x - 27 = (x + 9)(x - 3)
A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
x2 + 6x + 5 = (x + 1)(x + 5)
If: x2-6x-13 = 14 Then: x2-6x-27 = 0 And: (x+3)(x-9) = 0 So: x = -3 or x = 9
x2 + 6x - 27 = (x + 9)(x - 3)
Um.......is it x2+6x or x2-6x. I think your missing some things here champ
x2-6x-27 = (x+3)(x-9) when factored
X2 - 6X + 27 = 0 what are the factors of 27 that add to - 6? None! This polynomial is unreal and does not intersect the X axis.
x2 +6x = 27 x2 + 6x - 27 = 0 x2 + 9x - 3x - 27 = 0 x(x + 9) - 3(x + 9) =0 (x - 3)(x + 9) = 0 So x can equal 3 or -9.
324
x2 - 6x - 27 = (x-9)(x+3)
2x+6x=-9 => 8x=-9=> x=-8/9
With great difficulty not knowing if 6x and 27 are plus or minus
(x - 9)(x + 3)
A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}