please help on this x2+6x+27=
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x2 + 6x - 27 = (x + 9)(x - 3)
A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
x2 + 6x + 5 = (x + 1)(x + 5)