Yes. Any prime number greater than 100 has only itself in its prime factorization. Examples: The prime factorization of 101 is 101. The prime factorization of 109 is 109. The prime factorization of 127 is 127. The prime factorization of 311 is 311. The prime factorization of 691 is 691.
109 113 127 131
101 103 107 109 113
101, 103, 107, 109
109 109 x 1 This is all there is to the factor tree, because 109 is a prime number. Normally, I wouldn't use 1 in a factor tree, but I do in this case to make it clear that I have done a factor tree, since 109 is only divisible by itself and 1.
109 is a prime number.
Prime factorization of 109 = 1 * 109
109 is prime.
109 is a prime number.
The next prime number after 108 is 109.
1 & 109. It's a prime number.
109 and 1 is the only factor pair for 109.
109 is a prime number, so its only factors are 1 and 109.
yes
The prime numbers between the prime number 101 and the composite number 110 are 103, 107, and 109.
109 is prime. The others aren't.
It's only divisible by 1 and 109.