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No. i = square root of -1, and therefore imaginary. Only by squaring i can you have a real number.
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What is the real part of the complex number -2i?
It is 0. The number is wholly imaginary.
When the sum of the complex numbers 3 plus 2I and 6 - 4I is graphed in which quadrant does it lie?
3+2i + 6-4i = 9-2i The real part of this number is positive, therefore it lies in Q1 or Q4. The imaginary part is negative, therefore it is in Q3 or Q4. Q4 is the common possibility, therefore 9-2i is in Q4.
What is the imaginary number of square root of -4?
Either 2i or -2i, when squared equal -4.
What is a multiplicative inverse of an imaginary number?
The same as for a real number: 1 divided by the number.For example, the multiplicative inverse (or reciprocal) of 2i is 1 / 2i = -(1/2)i.
Is non-real numbers exist?
no, every number is a real number --- There are numbers that are not real numbers. They are called imaginary numbers, and have the property that when they are squared, the result is negative. The square root of -1 is called i, and the square root of any other negative number is i times the square root of the absolute value of the number. So the square root of -4 is 2i.
How do you divide complex numbers?
When dividing complex numbers you must:Write the problem in fractional formRationalize the denominator by multiplying the numerator and denominator by the conjugate of the denominator.You must remember that a complex number times its conjugate will give a real number.a complex number 2+2i. the conjugate to this is 2-i1. Multiply both together gives a real number.(2+2i)(2-2i) = 4 -4i + 4i + (-4i2) (and as i2 = -1) = 8To divide a complex number by a real number simply divide the real parts by the divisor.(8+4i)/2 = (4+2i)To divide a real number by a complex number.1. make a fraction of the expression 8/(2+2i)2. multiply by 1. express 1 as a fraction of the divisor's conjunction. 8/(2+2i)*(2-2i)/(2-2i)3. multiply numerator by numerator and denominator by denominator.(16-16i)/84. and simplify 2-2i
What is conjugation of 7-2i?
The conjugate of a complex number can be found by multiplying the imaginary part by -1, then adding the "real" part back. (-2i) * -1 = 2i, so the conjugation is 7+2i
What is the real part of the complex number -2i?
It is 0. The number is wholly imaginary.
How many fourth roots will a positive real number have?
In general, the answer is 4, but only 2 of them are real. For example, the 4th roots of 16 are 2, -2, 2i, and -2i.
Can x to the fourth power ever result in a negative number?
no even exponent of a real number can ever result in a negative number. If x is a complex number with the real and imaginary part having the same magnitude, then taking that to the fourth power will result in a real number, which is negative.Example: (2 + 2i)4, or (-2 + 2i)4, or (2 - 2i)4, or (-2 - 2i)4, Just take (2 - 2i)4, as one to see how it works. First take (2 - 2i)2, then we'll square that result.(2 - 2i)2 = 4 - 4i - 4i + 4i2 , but i2 is -1, so we have -8i, then square that is 64i2 which is -64.
Is The sum of two complex numbers is sometimes a real number.?
Sure, if the imaginary part is opposite. For example:(3 + 2i) + (5 - 2i) = 8
Is a square root of a negative number a real number?
no, it is an imaginary number represented by an i. For example, the square root of -4 is 2i.
Can you figure out two complex numbers that when mulitplied together become a real number?
3 and 5 are both complex numbers, and if you multiply them together, you get 15, which is a real number. If you were looking for two non-real complex numbers, then any pair of complex conjugates will work. For example, 5+2i times 5-2i is 29.
The conjugate of the complex number 3 plus 2i is?
It is 3 minus 2i
When the sum of the complex numbers 3 plus 2I and 6 - 4I is graphed in which quadrant does it lie?
3+2i + 6-4i = 9-2i The real part of this number is positive, therefore it lies in Q1 or Q4. The imaginary part is negative, therefore it is in Q3 or Q4. Q4 is the common possibility, therefore 9-2i is in Q4.
X2 plus x equals 3x-5?
x2 +x=3x-5 so x2 -2x+5=0 which does not factor ( over the real numbers) so you can either complete the square of use the quadratic equation to solve. Let's complete the square. (x-1)2 =-4 x-1= plus of minus 2i so x=1+2i or x=1-2i Now check it just as you would a real answer. 1+2i -1 is 2i and 2i squared is -4 as desired Now 1-2i-1 is -2i and (-2i) squared is -4 also. We know the answer is not real if we simply calculated the discriminant. b2 -4ac=4-4(5)<0 so there are no real answers as we found.
What is the imaginary number of square root of -4?
Either 2i or -2i, when squared equal -4.
