no. because there are more composite numbers than prime numbers It depends on the place you choose to pick the Prime number (e.g. 457 or 7577?). The bigger the number the less likely it is a prime.
A formula gives the probability for a number being prime (Prime Number Theorem).
"The probability of getting a prime number in a die is 4/6" Actually there are 3 prime numbers on a die. 2, 3, and 5 are all prime numbers. So this tells you that you have 3 chances it will be a prime number and 3 chances it will not be a prime number. So the probability of getting a prime number on a die would be 3/6 or 1/2.
The probability of getting at least one prime number in two dice is 3/4.
The probability is 3 out of 10.
The probability of rolling an even number on a die is 3 in 6 or 1 in 2. The probability of rolling a prime on a die is 3 in 6 or 1 in 2, but one of those primes is also even. Simply add the probabilities and you find that the probability of rolling an even number or a prime on a die is 5 in 6.
53 is the first prime number greater than 50.
no.
No.
The probability is 8/20.
Although there are infinitely many primes, they become rarer and rarer so that as the number of numbers increases, the probability that picking one of them at random is a prime number tends to zero*. In the first 10 numbers there are 4 primes, so the probability of picking one is 4/10 = 2/5 = 0.4 In the first 100 numbers there are 26 primes, so the probability of picking one is 25/100 = 1/4 = 0.25 In the first 1,000 numbers there are 169 primes, so the probability of picking one is 168/1000 = 0.168 In the first 10,000 numbers there are 1,229 primes, so the probability of picking one is 0.1229 In the first 100,000 numbers there are 9592 primes, so the probability of picking one is 0.09592 In the first 1,000,000 numbers there are 78,498 primes, so the probability of picking one is 0.078498 In the first 10,000,000 numbers there are 664,579 primes, so the probability of picking one is 0.0664579 * Given any small value ε less than 1 and greater than 0, it is possible to find a number n such that the probability of picking a prime at random from the numbers 1-n is less than the given small value ε.
First you need to work out the probability of rolling a prime number. The prime numbers on a die are 2, 3 and 5. Thus the probability of rolling a prime number is 3/6 which can be simplified to 1/2. The probability of rolling a number greater than 1 is 5/6. The probability of rolling one on one dice and one on the other is therefore 1/2 x 5/6 = 5/12. There are two possible ways round these options could come though. You might get the number greater than one on the first roll, and the prime on the second. Thus we need to multiply the probability by 2, which gives us the final answer of 5/6.
Half
When a fair die is thrown the probability that a prime number will occur is 2:1
"The probability of getting a prime number in a die is 4/6" Actually there are 3 prime numbers on a die. 2, 3, and 5 are all prime numbers. So this tells you that you have 3 chances it will be a prime number and 3 chances it will not be a prime number. So the probability of getting a prime number on a die would be 3/6 or 1/2.
There are a number of asymptotic distributions developed by various mathematicians. A simple one to sues is that, given an integer N, the probability that a random positive integer which is not greater than N is prime is very close to 1 / ln(N) where ln(N) is the natural logarithm of N..
least prime number greater 60 = 61
53 is a prime number that is greater than 50
The probability of getting at least one prime number in two dice is 3/4.