36g2h2 = 2*2*3*3*g*g*h*h provided g and h are prime.
45/1000 as a decimal is 0.045
I assume that "Th,3" is translation by "h" in the x direction and "3" in the y direction- that is, that Th,3(x, y)= (x+h, y+3)- and that "T-2, k" is translation by "-2" in the x direction and "k" in the y direction- that is, that T-2,k(x,y)= (x-2, y+ k). If that is so then Th,3 x T-2,k(-3, 0)= Th,3(-3-2, 0+k)= Th,3(-5,k)= (-5+h, 3+k)= (-4,8). That is, -5+h= -4 and 3+ k= 8. Now, what are h and k? Once you know that, finding Th,3x T-2,k(2, -1) should be easy.
It is 3:1. This is because volume of a cone is pi/3*r*r*h while vol of a cylinder is pi*r*r*h.
24
3+2h
A number h increased by i.e. added to itself = h + h =2h
Buddha Monks(Set of 3) Statue Figurine Sculpture H – 20 cm
A Verbal Scentence is a scentence containging clues about an equatioin with in the problem. a number k times 2 increased by 6. K2+6 5 less than a number h increased by 3 is 11 h-5+3=11 Hope this helps you guy's!;]
Area = 2*L*W + 2W*H + 2*H*L where L = length, W = width and H = height So A = 2*20*7 + 2*7*3 + 2*3*20 = 280 + 42 + 120 = 442 sq units.
3. T=20, h=8, e=5.
A car driving 121 km/h will travel 403,33 km in 3 hours 20 minutes. 20 minutes equals 1/3 hour. 121 km/h * 3 1/3 hour = 403 1/3 km
80/3 ft Reason: 20 = 1/2 bh , h=2b 40 = bh 40 = 3b b = 40/3 , h = 80/3
h/20
Suppose the number of Heads is H where H = 0, 1, 2, 3 ,4. Then the number of Tails is 4-H. Their product is X = H*(4-H) = 0, 3, 4, 3, 0 Thus X is NOT more than 1 only if H = 0 or H = 4 The probability of each of these events is 2-4 and so their combined probability is 2-3 = 1/8. Therefore, Prob(X > 1 ) = 1 / 1/8 = 7/8
Suppose the old length and height were l and h and the new ones L and H. And let v and V be the old and new volumes. Then increase the length by 50% means L = 1.50*l and increase height by 20% means H = 1.20*h Then V/v = LHW/lhw = LH/lh (assuming width is left unchanged) = 1.5*l * 1.2*h /l*h = 1.5*1.2 = 1.8 That is V = 1.8*v The room has increased by 80 per cent.
It is the product of molar concentration of H* and OH-