3h + 20
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36g2h2 = 2*2*3*3*g*g*h*h provided g and h are prime.
I assume that "Th,3" is translation by "h" in the x direction and "3" in the y direction- that is, that Th,3(x, y)= (x+h, y+3)- and that "T-2, k" is translation by "-2" in the x direction and "k" in the y direction- that is, that T-2,k(x,y)= (x-2, y+ k). If that is so then Th,3 x T-2,k(-3, 0)= Th,3(-3-2, 0+k)= Th,3(-5,k)= (-5+h, 3+k)= (-4,8). That is, -5+h= -4 and 3+ k= 8. Now, what are h and k? Once you know that, finding Th,3x T-2,k(2, -1) should be easy.
It is 3:1. This is because volume of a cone is pi/3*r*r*h while vol of a cylinder is pi*r*r*h.
A.) j(a) = a^2 - 2a + 4 B.) j(3) = (3)^2 - 2(3) + 4 = 9 - 6 + 4 = 7 C.) j(x^2) = (x^2)^2 - 2(x^2) + 4 = x^4 - 2x^3 + 4 D.) j(x+3) = (x + 3)^2 - 2(x + 3) + 4 = x^2 +6x + 9 - 2x - 6 + 4 = x^2 + 4x + 7 E.) j(x+h) = (x + h)^2 - 2(x + h) + 4 = x^2 + 2hx + h^2 - 2x - 2h + 4
A.) j(a) = a^2 - 2a + 4 B.) j(3) = (3)^2 - 2(3) + 4 = 9 - 6 + 4 = 7 C.) j(x^2) = (x^2)^2 - 2(x^2) + 4 = x^4 - 2x^3 + 4 D.) j(x+3) = (x + 3)^2 - 2(x + 3) + 4 = x^2 +6x + 9 - 2x - 6 + 4 = x^2 + 4x + 7 E.) j(x+h) = (x + h)^2 - 2(x + h) + 4 = x^2 + 2hx + h^2 - 2x - 2h + 4