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Q: What's the highest decimal number that be represented with 5 binary digits?

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In binary this would be written as 1011. This is because in binary (from right to left) the digits in this number mean: (1 * 20) + (1 * 21) + (0 * 22) + (1 * 23). This, of course, is equal to (1 * 1) + (1 * 2) + (0 * 4) + (1 * 8), which equals 1 + 2 + 0 + 8, which equals 11 (in decimal).

It is 216 - 1 = 65535.

1111111111b = 1023d When converting a binary number in which every digit is a one, there is an easy trick to doing it: take the number of digits, in this case 10, raise the base to that power 210 = 1024 , then subtract one. 210 - 1 = 1023. If the reason for this isn't clear, it may be easier to think of it in decimal. Remember that 1 is the highest valued digit in binary. Similarly, 9 is the highest digit in decimal. So in decimal, the number 99999 can also be looked at as 105 - 1 = 100000 - 1 = 99999

The decimal number "27" is written in binary as 11011.This is because binary has a base of 2. This means that the digits are representing multiples of powers of 2 (as opposed to 10 in decimal). This number in binary means (1 * 20) + (1 * 21) + (0 * 22) + (1 * 23) + (1 * 24). In decimal this equals 1 + 2 + 0 + 8 + 16. This, of course, equals 27.

Binary uses only the digits 0 and 1.

Related questions

11111111 = 255

It is 31.

The binary number 10101000 = 168

10 digits.

Binary digits are 1 and 0 0 = 0 1 = 1 10 = 2 11 = 3 100 = 4 101 = 5 110 = 6 111 = 7 1000 = 8 So, 11 in binary is the highest which can be formed with two digits - and that equals 3 in decimal (base 10) numbering.

56 in binary is 111000. Unlike the decimal number system where we use the digits.

It takes 7 digits.

All I know is that when a number is negative, you convert the decimal into binary and if it is negative you put 1111 before the binary digits.

99

Octet

64 or 123

162 - 1 = 255 Strictly speaking the highest value is FF which, in decimal is 1515 = 4.38*1017 or approx 438 quadrillion.

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