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What are the factors of a polynomial function with zeros at -2 and 7?
Wiki User
∙ 13y ago
Since there are two zeros, we have:
y = (x - (-2))(x - 7)
y = (x + 2)(x - 7)
Wiki User
∙ 13y ago
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What are the zeros of a polynomial function?
the zeros of a function is/are the values of the variables in the function that makes/make the function zero. for example: In f(x) = x2 -7x + 10, the zeros of the function are 2 and 5 because these will make the function zero.
What is a cubic polynomial function in standard form with zeros 1 -2 and 2?
It is x^3 - x^2 - 4x + 4 = 0
What is a zero of polynomial function?
A zero of a polynomial function - or of any function, for that matter - is a value of the independent variable (often called "x") for which the function evaluates to zero. In other words, a solution to the equation P(x) = 0. For example, if your polynomial is x2 - x, the corresponding equation is x2 - x = 0. Solutions to this equation - and thus, zeros to the polynomial - are x = 0, and x = 1.
What is a quadratic function is a function whose rule is a polynomial of degree what?
A polynomial of degree 2.
How do you use quadratic formula on ti 89?
The function on a ti-89 that gives you the zeros of a quadratic equation is called just that "zeros". To access it from the home screen, press f2 and select the label called "zeros(" then type the function and define the variable. For example: if you want the zeros of y=x^2+7x+12 you the display should read: zeros(x^2+7x+12,x), press enter and it will give you the results in this case {-3, -4}. We can check if it did it right by factoring this simple quadratic. 0=x^2+7x+12 factors as 0=(x+3)(x+4) set the factors equal to zero: x+3=0 x=-3 x+4=0 x=-4 So we see that the calculator did it right! That is always a good thing. This will work for most polynomial functions.
What are the zeros of a polynomial function?
the zeros of a function is/are the values of the variables in the function that makes/make the function zero. for example: In f(x) = x2 -7x + 10, the zeros of the function are 2 and 5 because these will make the function zero.
When the zeros of a polynomial function are 1 divided by2 and negative 1 what is the function?
Any multiple of X^2+X/2-1/2
What is a cubic polynomial function in standard form with zeros 1 -2 and 2?
It is x^3 - x^2 - 4x + 4 = 0
Formula for finding zeros of polynomial function?
Try the quadratic formula. X = -b ± (sqrt(b^2-4ac)/2a)
What is a zero of polynomial function?
A zero of a polynomial function - or of any function, for that matter - is a value of the independent variable (often called "x") for which the function evaluates to zero. In other words, a solution to the equation P(x) = 0. For example, if your polynomial is x2 - x, the corresponding equation is x2 - x = 0. Solutions to this equation - and thus, zeros to the polynomial - are x = 0, and x = 1.
If you are asked to write a polynomial function of least degree with real coefficients and with zeros of 2 and i square roots of seven what would be the degree of the polynomial also wright equation?
3y2-5xyz yay i figured it out!!!!
What is a quadratic function is a function whose rule is a polynomial of degree what?
A polynomial of degree 2.
What is the difference between rational and polynomials?
A polynomial function is simply a function that is made of one or more mononomials. For example 4x^2+3x-5 A rational function is when a polynomial function is divided by another polynomial function.
What is a zero of a function?
Assuming the polynomial is written in terms of "x": It means, what value must "x" have, for the polynomial to evaluate to zero? For example: f(x) = x2 - 5x + 6 has zeros for x = 2, and x = 3. That means that if you replace each "x" in the polynomial with 2, for example, the polynomial evaluates to zero.
Is it always true that between any two zeros of the derivative of any polynomial there is a zero of the polynomial?
No. Consider the polynomial: f(x) = x3 + 4x2 + 4x + 16 then f'(x) = 3x2 + 8x + 4 = (3x + 2)(x + 2) => x = -2/3, -2 are the zeros of f'(x) Using the second derivative: f''(x) = 6x + 8 it can be seen that: f''(-2) = -4 -> x = -2 is a maximum f''(-2/3) = +4 -> x = -2/3 is a minimum But plugging back into the original polynomial: f(-2) = 16 f(-2/3) = 14 22/27 Between the zeros of the first derivative, the slope of the polynomial is negative so that the polynomial is always decreasing in value, but as the polynomial is greater than zero at the zeros of the first derivative, it cannot become zero between them. That is it has no zeros between the zeros of its first derivative f(x) = x3 + 4x2 + 4x + 16 = (x + 4)(x2 + 4) has only 1 zero at x = -4.
If the factors of a polynomial are x - 2 and x - 5 what values of x make that polynomial 0?
2 or 5
How do you use quadratic formula on ti 89?
The function on a ti-89 that gives you the zeros of a quadratic equation is called just that "zeros". To access it from the home screen, press f2 and select the label called "zeros(" then type the function and define the variable. For example: if you want the zeros of y=x^2+7x+12 you the display should read: zeros(x^2+7x+12,x), press enter and it will give you the results in this case {-3, -4}. We can check if it did it right by factoring this simple quadratic. 0=x^2+7x+12 factors as 0=(x+3)(x+4) set the factors equal to zero: x+3=0 x=-3 x+4=0 x=-4 So we see that the calculator did it right! That is always a good thing. This will work for most polynomial functions.
