Since there are two zeros, we have:
y = (x - (-2))(x - 7)
y = (x + 2)(x - 7)
the zeros of a function is/are the values of the variables in the function that makes/make the function zero. for example: In f(x) = x2 -7x + 10, the zeros of the function are 2 and 5 because these will make the function zero.
It is x^3 - x^2 - 4x + 4 = 0
A zero of a polynomial function - or of any function, for that matter - is a value of the independent variable (often called "x") for which the function evaluates to zero. In other words, a solution to the equation P(x) = 0. For example, if your polynomial is x2 - x, the corresponding equation is x2 - x = 0. Solutions to this equation - and thus, zeros to the polynomial - are x = 0, and x = 1.
A polynomial of degree 2.
The function on a ti-89 that gives you the zeros of a quadratic equation is called just that "zeros". To access it from the home screen, press f2 and select the label called "zeros(" then type the function and define the variable. For example: if you want the zeros of y=x^2+7x+12 you the display should read: zeros(x^2+7x+12,x), press enter and it will give you the results in this case {-3, -4}. We can check if it did it right by factoring this simple quadratic. 0=x^2+7x+12 factors as 0=(x+3)(x+4) set the factors equal to zero: x+3=0 x=-3 x+4=0 x=-4 So we see that the calculator did it right! That is always a good thing. This will work for most polynomial functions.
the zeros of a function is/are the values of the variables in the function that makes/make the function zero. for example: In f(x) = x2 -7x + 10, the zeros of the function are 2 and 5 because these will make the function zero.
Any multiple of X^2+X/2-1/2
It is x^3 - x^2 - 4x + 4 = 0
Try the quadratic formula. X = -b ± (sqrt(b^2-4ac)/2a)
A zero of a polynomial function - or of any function, for that matter - is a value of the independent variable (often called "x") for which the function evaluates to zero. In other words, a solution to the equation P(x) = 0. For example, if your polynomial is x2 - x, the corresponding equation is x2 - x = 0. Solutions to this equation - and thus, zeros to the polynomial - are x = 0, and x = 1.
3y2-5xyz yay i figured it out!!!!
A polynomial of degree 2.
A polynomial function is simply a function that is made of one or more mononomials. For example 4x^2+3x-5 A rational function is when a polynomial function is divided by another polynomial function.
Assuming the polynomial is written in terms of "x": It means, what value must "x" have, for the polynomial to evaluate to zero? For example: f(x) = x2 - 5x + 6 has zeros for x = 2, and x = 3. That means that if you replace each "x" in the polynomial with 2, for example, the polynomial evaluates to zero.
No. Consider the polynomial: f(x) = x3 + 4x2 + 4x + 16 then f'(x) = 3x2 + 8x + 4 = (3x + 2)(x + 2) => x = -2/3, -2 are the zeros of f'(x) Using the second derivative: f''(x) = 6x + 8 it can be seen that: f''(-2) = -4 -> x = -2 is a maximum f''(-2/3) = +4 -> x = -2/3 is a minimum But plugging back into the original polynomial: f(-2) = 16 f(-2/3) = 14 22/27 Between the zeros of the first derivative, the slope of the polynomial is negative so that the polynomial is always decreasing in value, but as the polynomial is greater than zero at the zeros of the first derivative, it cannot become zero between them. That is it has no zeros between the zeros of its first derivative f(x) = x3 + 4x2 + 4x + 16 = (x + 4)(x2 + 4) has only 1 zero at x = -4.
2 or 5
The function on a ti-89 that gives you the zeros of a quadratic equation is called just that "zeros". To access it from the home screen, press f2 and select the label called "zeros(" then type the function and define the variable. For example: if you want the zeros of y=x^2+7x+12 you the display should read: zeros(x^2+7x+12,x), press enter and it will give you the results in this case {-3, -4}. We can check if it did it right by factoring this simple quadratic. 0=x^2+7x+12 factors as 0=(x+3)(x+4) set the factors equal to zero: x+3=0 x=-3 x+4=0 x=-4 So we see that the calculator did it right! That is always a good thing. This will work for most polynomial functions.