-(3x - 4)(x - 2)
(3x+1)(x+2)
It is: (-3x-4)(x+2) when factored
While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2
factor out a 3x 3x(x-3)=3x2-9x
3x2-7x+4 = (3x-4)(x-1) when factored
(3x - 4)(x - 1)
If you set your equation to equal 7, then you can move 7 to the other side of the equation, and solve for x. This/these values will always result in 7. e.g. 3x2+11x+6=7 3x2+11x+6-7=7-7 3x2+11x-1=0 Factor using the quadratic formula and solve for x.
[ x3 + 3x2 + 2x ] is a trinomial. It's factors are [ x, (x + 1), (x + 2) ] .
3x2 - 11x - 4 = (x-4)(3 x + 1)
If you mean: 27x2-90x+27 then divide all terms by 9 which is then 3x2-10x+3 And when factored it is: (3x-1)(x-3)
11 is a prime number. Its only factors are one and itself.
Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.
3x2 + 36x + 81 = 3(x2 + 13x + 27)
3x2+7-6 = (3x-2)(x+3) when factored
Yes. (Assuming that -3x2 is the best representation of 3x2 that this browser will allow.)
-(3x - 4)(x - 2)