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3x2 + 10x - 8The auxiliary equation is 3x2 + 10x - 24 [because 8*3 = 24]
Two factors of -24 which sum to 10 are 12 and -2.
So the factorisation of the auxillary is (3x + 12)*(3x - 2) = 3*(x + 4)*(3x - 2)
Dividing by the 3 used to create the auxiliary gives the solution as (x + 4)*(3x - 2).
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