2520 is the smallest multiple of of first ten natural numbers.
The sum of the first 50 natural numbers is 1,251.
1 Sum of first n natural numbers = n(n+1)2[Formula.]2 Arthmetic mean of first n natural numbers = Sum of the numbers n[Formula.]3 = n(n+1)2n = n+124 So, the Arthmetic mean of first n natural numbers = n+12
No. A simple example is 5 - 6 = -1. Two natural numbers (5 and 6) are used to subtract to -1 (which isn't a natural number).
1,2,
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
Good question. 1+2+3+4+5=155=15 So the product of first five natural numbers is fifteen Natural numbers starts from one So we add first five natural numbers and get the right answer is fifteen
Π5j=1 (j)=1x2x3x4x5=5!=120
5.
The natural numbers from 1 to 12 are: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 The prime numbers between 1 and 12 are: 2, 3, 5, 7, 11 This is a total of 5/12 prime numbers.
No. All natural numbers are whole numbers greater than zero. Think of natural numbers as the numbers you count with. 1 2 3 4 5 6... and so on.
2520 is the smallest multiple of of first ten natural numbers.
The natural numbers are the whole numbers 1 2 3 4 5 .... and so on
natural numbers are 1, 2, 3, 4, 5.......... whole numbers are natural numbers including 0, i.e., 0, 1, 2, 3, 4, 5..........
The sum of the first 50 natural numbers is 1,251.
1 Sum of first n natural numbers = n(n+1)2[Formula.]2 Arthmetic mean of first n natural numbers = Sum of the numbers n[Formula.]3 = n(n+1)2n = n+124 So, the Arthmetic mean of first n natural numbers = n+12
The sum of the first 200 natural numbers is 20,001.