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Euclid proved that 2p−1(2p−1) is an even perfect number whenever 2p−1 is prime.

For example, the first four perfect numbers are generated by the formula 2p−1(2p−1), with p a Prime number, as follows: for p = 2: 21(22−1) = 6for p = 3: 22(23−1) = 28for p = 5: 24(25−1) = 496for p = 7: 26(27−1) = 8128.

All very true, but the question isn't about perfect numbers. The first four numbers that would satisfy the question's requirements are 1, 2, 3 and 5. If you feel 1 shouldn't be included, it would be 2, 3, 5 and 7 because only prime numbers are equal to the product of their factors.

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Q: What are the first four numbers which are equal to the product of all their factors?
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