Euclid proved that 2p−1(2p−1) is an even perfect number whenever 2p−1 is prime.
For example, the first four perfect numbers are generated by the formula 2p−1(2p−1), with p a Prime number, as follows: for p = 2: 21(22−1) = 6for p = 3: 22(23−1) = 28for p = 5: 24(25−1) = 496for p = 7: 26(27−1) = 8128.
All very true, but the question isn't about perfect numbers. The first four numbers that would satisfy the question's requirements are 1, 2, 3 and 5. If you feel 1 shouldn't be included, it would be 2, 3, 5 and 7 because only prime numbers are equal to the product of their factors.
The first five prime numbers are 2, 3, 5, 7, 11. The product of these five numbers is equal to 2 x 3 x 5 x 7 x 11 = 2310.
The product of the GCF and LCM of two numbers is equal to the product of the two numbers. The other number is 126.
The product of the first three prime numbers (2, 3, and 5) is 30.
The first four prime numbers are 2, 3, 5, 7. The product of these numbers is 2 x 3 x 5 x 7 = 210
Sure thing, honey. The first four prime numbers are 2, 3, 5, and 7. Multiply those bad boys together and you get 210. And wouldn't you know it, 210 is a composite number because it can be divided by numbers other than 1 and itself. Math can be a real hoot sometimes, can't it?
The product of two whole numbers depends on what the numbers are. The operation is multiplication.11 and 8. You find the factors of 88 first. Then find which 2 will subtract to equal 3
Yes because the product of the first 17 prime numbers will have 17 factors
The first prime numbers are 2, 3, 5, 7, 11. When multiplied together the product is 2310. It is the smallest number that has the first five numbers as its factors.
The first five prime numbers are 2, 3, 5, 7, 11. The product of these five numbers is equal to 2 x 3 x 5 x 7 x 11 = 2310.
The product of the GCF and LCM of two numbers is equal to the product of the two numbers. The other number is 126.
It means to express a number as the product of its factors. Factors are either composite numbers or prime numbers (except that 0 and 1 are neither prime nor composite).
The product of the first and fourth prime numbers (2 x 7) is 14. No two consecutive odd numbers add up to 14.
If you know that the product of 2 negative numbers is positive, then the product of 4 negative numbers has to be positive. The product of the first two negative numbers is positive and the next two negative numbers is positive. Multiplying the product of the first two numbers (positive number) and the product of the last two numbers (also positive), is a positive number times a positive number which is positive. Let a, b, c and d be negative numbers: (a*b*c*d) = (a*b)*(c*d) (-ve*-ve*-ve*-ve)=(-ve*-ve)*(-ve*-ve)= (+ve)*(+ve) = (+ve)
First, we are not interested for the sign of the numbers, because the product of two negative numbers is always positive, so we need to find the two consecutive factors of 240, which are 15 and 16. Thus, the numbers are -16 and -15.
A prime number is a number that's only factors are the number itself and one. So, the first two prime numbers after forty are forty-one and forty-three. Forty-one multiplied by forty-three is equal to one thousand, seven hundred, sixty-three.
Because two negative multiplied together equal a positive. So after the first multiplication we have a positive and a negative. When we multiply these we have a negative.
The first three even numbers are 2, 4, and 6. To find the product of these numbers, you simply multiply them together: 2 x 4 x 6 = 48. Therefore, the product of the first three even numbers is 48.