Well, honey, the numbers divisible by both 3 and 4 are the multiples of their least common multiple, which is 12. So, any number that can be divided by 12 without leaving a remainder is your answer. Get ready to do some division or just use that brain of yours to figure it out!
There aren't any prime numbers divisible by 4. Prime numbers aren't divisible by anything except 1 and the number.
3 <><><> 3 is only divisible by 1 and itself. whereas 4 and 10 are divisible by other numbers. 4 is divisible by 1,2,4. 10 is divisible by 1,2,5,10 <><><> A prime number is a number that is evenly divisible only by itself and one. Therefore, 3 is the prime number. 4 is divisible by 1, 2, and 4. 10 is divisible by 1, 2, 5, and 10. Three cannot be divided evenly by any other whole number. So, 3 is the prime number.
Clearly, both 810 and 910 are divisible by 5. A wee trick regarding numbers that are a multiple of 3, is that the component numbers, when added together, are divisible by three. So, 654 is divisible by 3, as 6+5+4 = 15 which is divisible by 3. In your example, 810 components add up to 9, which is divisible by 3. But the components of 910 add up to 10 which is not so divisible.
Not all even numbers are divisible by 6. These numbers are not evenly divisible by 6: Any number smaller than 6. Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.
Oh, dude, you're hitting me with the math questions, huh? So, numbers that are divisible by both 3 and 4 are multiples of their least common multiple, which is 12. That means any number that can be divided by both 3 and 4 is like 12, 24, 36, and so on. But hey, who's counting, right?
All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
0,12,24,36,48,60,72,84, and 96 are the numbers between 0 and 100 that are divisible by both 3 and 4.
No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.
12 is the Lowest Common Multiple
No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9
12 and its multiples
All 4 digit numbers that are divisible by 9 are also divisible by 3. The first is 1008 and the last is 9999.
432 is divisible by 3 and 4 because the quotients are whole numbers. 432/3 = 144 432/4 = 108
100 ÷ 4 = 25 → 24 numbers between 0 and 100 exclusive are divisible by 4 100 ÷ 6 = 16 2/3 → 16 numbers between 0 and 100 are divisible by 6 lcm(4, 6) = 12 → 100 ÷ 12 = 8 1/3 → 8 numbers between 0 and 100 are divisible by 4 and 6.
2999 of them.
1, 2 and 3
50