Well, honey, the numbers divisible by both 3 and 4 are the multiples of their least common multiple, which is 12. So, any number that can be divided by 12 without leaving a remainder is your answer. Get ready to do some division or just use that brain of yours to figure it out!
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Numbers that are divisible by both 3 and 4 are multiples of the least common multiple of 3 and 4, which is 12. Therefore, the numbers divisible by 3 and 4 are any integer that can be expressed as 12n, where n is an integer. This includes numbers like 12, 24, 36, and so on.
There aren't any prime numbers divisible by 4. Prime numbers aren't divisible by anything except 1 and the number.
3 <><><> 3 is only divisible by 1 and itself. whereas 4 and 10 are divisible by other numbers. 4 is divisible by 1,2,4. 10 is divisible by 1,2,5,10 <><><> A prime number is a number that is evenly divisible only by itself and one. Therefore, 3 is the prime number. 4 is divisible by 1, 2, and 4. 10 is divisible by 1, 2, 5, and 10. Three cannot be divided evenly by any other whole number. So, 3 is the prime number.
Clearly, both 810 and 910 are divisible by 5. A wee trick regarding numbers that are a multiple of 3, is that the component numbers, when added together, are divisible by three. So, 654 is divisible by 3, as 6+5+4 = 15 which is divisible by 3. In your example, 810 components add up to 9, which is divisible by 3. But the components of 910 add up to 10 which is not so divisible.
Not all even numbers are divisible by 6. These numbers are not evenly divisible by 6: Any number smaller than 6. Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.
Oh, dude, you're hitting me with the math questions, huh? So, numbers that are divisible by both 3 and 4 are multiples of their least common multiple, which is 12. That means any number that can be divided by both 3 and 4 is like 12, 24, 36, and so on. But hey, who's counting, right?