Oh, dude, you're hitting me with the math questions, huh? So, numbers that are divisible by both 3 and 4 are multiples of their least common multiple, which is 12. That means any number that can be divided by both 3 and 4 is like 12, 24, 36, and so on. But hey, who's counting, right?
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Well, isn't that a happy little question! When you're looking for numbers that are divisible by both 3 and 4, you can find them by looking for numbers that are divisible by the least common multiple of 3 and 4, which is 12. So, any number that is a multiple of 12 will be divisible by both 3 and 4. Just imagine those numbers peacefully coexisting, creating a harmonious mathematical landscape.
Numbers that are divisible by both 3 and 4 are also divisible by their least common multiple, which is 12. This means that any number that is a multiple of 12 will be divisible by both 3 and 4. Examples of such numbers include 12, 24, 36, 48, and so on.
12 24 36 48 60 72 84 96 108 120
and so on ...
Example: 4 x 21 = 84 = 3 x 28
12 24 36 48 60 72 84 96 108 120
and so on ...
Example: 4 x 21 = 84 = 3 x 28
Well, honey, the numbers divisible by both 3 and 4 are the multiples of their least common multiple, which is 12. So, any number that can be divided by 12 without leaving a remainder is your answer. Get ready to do some division or just use that brain of yours to figure it out!
Clearly, both 810 and 910 are divisible by 5. A wee trick regarding numbers that are a multiple of 3, is that the component numbers, when added together, are divisible by three. So, 654 is divisible by 3, as 6+5+4 = 15 which is divisible by 3. In your example, 810 components add up to 9, which is divisible by 3. But the components of 910 add up to 10 which is not so divisible.
a number is 6. All numbers divisible by both 4 and 15 are the multiples of 4 and 15. Since 4 and 15 have no prime factor in common (4 = 22, 15 = 3 · 5), then the least common multiple of 4 and 15 is equal to their product, namely 4 · 15 = 60. Every other multiple of 4 and 15 is divisible by 60. Thus, if 60 is divisible by a number then all the multiples of 4 and 15 are divisible by that number. Therefore, it is enough to check by which number in the given options is 60 divisible. Only 6 divides 60 and none of the other do. The answer must be (A).
Oh, dude, you're looking for numbers that are divisible by both 4 and 7? Well, when those two get together and have a party, their love child numbers are like 28, 56, 84, and so on. It's like a cool math club where only the multiples of 4 and 7 are allowed to hang out.
Numbers that are divisible by both 4 and 5 are multiples of the least common multiple of 4 and 5, which is 20. Therefore, numbers that are divisible by 4 and 5 are multiples of 20. In other words, any number that can be expressed as 20 multiplied by an integer (e.g., 20, 40, 60, 80, etc.) is divisible by both 4 and 5.