12 24 36 48 60 72 84 96 108 120
and so on ...
Example: 4 x 21 = 84 = 3 x 28
12 24 36 48 60 72 84 96 108 120
and so on ...
Example: 4 x 21 = 84 = 3 x 28
(12,24,36,48,)
Clearly, both 810 and 910 are divisible by 5. A wee trick regarding numbers that are a multiple of 3, is that the component numbers, when added together, are divisible by three. So, 654 is divisible by 3, as 6+5+4 = 15 which is divisible by 3. In your example, 810 components add up to 9, which is divisible by 3. But the components of 910 add up to 10 which is not so divisible.
a number is 6. All numbers divisible by both 4 and 15 are the multiples of 4 and 15. Since 4 and 15 have no prime factor in common (4 = 22, 15 = 3 · 5), then the least common multiple of 4 and 15 is equal to their product, namely 4 · 15 = 60. Every other multiple of 4 and 15 is divisible by 60. Thus, if 60 is divisible by a number then all the multiples of 4 and 15 are divisible by that number. Therefore, it is enough to check by which number in the given options is 60 divisible. Only 6 divides 60 and none of the other do. The answer must be (A).
Multiples of 12.
There aren't any prime numbers divisible by 4. Prime numbers aren't divisible by anything except 1 and the number.
3 <><><> 3 is only divisible by 1 and itself. whereas 4 and 10 are divisible by other numbers. 4 is divisible by 1,2,4. 10 is divisible by 1,2,5,10 <><><> A prime number is a number that is evenly divisible only by itself and one. Therefore, 3 is the prime number. 4 is divisible by 1, 2, and 4. 10 is divisible by 1, 2, 5, and 10. Three cannot be divided evenly by any other whole number. So, 3 is the prime number.
The numbers divisible by both 3 and 4 are multiples of 12, thus between 10 and 99: 12, 24, 36, 48, 60, 72, 84, 96 are the numbers divisible by both 3 and 4.
0,12,24,36,48,60,72,84, and 96 are the numbers between 0 and 100 that are divisible by both 3 and 4.
1, 2 and 3
12 is the Lowest Common Multiple
There are 75 whole numbers from 100 to 999 that are divisible by both three and four.
33 divisible by 3. 14 divisible by 7. 4 divisible by both. Total: 43
There is only one number that can be divisible by both 3 and 4 yet not greater than 20, 12.
All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
Yes.Two tests for divisibility by 4:If the last two digits are divisible by 4 the whole number is divisible by 4. (In both cases, the last two digits are 52 and 52 is divisible by 4 (52 = 4 x 13), so the original numbers are both divisible by 4.)Add the units digit to twice the tens digit; if this sum is divisible by 4, so is the original number. (In both cases: 2 + 2x5 = 12 which is divisible by 4 (12 = 4 x 3), so the original numbers are both divisible by 4.)
No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.
Yes.
4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,92,96,100 ............ on and on and on to infinity and beyond LOL !!!!!!!!!