The set of complex numbers includes the set of real numbers. The real number system is just with the imaginary part set to 0.
example: z = 5 + i0 = 5
So the simple answer would be (2+i0)*(5+i0) = 10, so the complex values (2,0) and (5,0) get the result your looking for.
If you want a pair not on the real line then 2*exp(i*pi/4) and 5*exp(-i*pi/4) will do.
If you multiply the two complex numbers you get 2*5*exp(i*(pi/4-pi/4)) which is just 10.
Since pure imaginary numbers are also part of the set of complex numbers, you could have -2i * 5i, the i's multiplied together yield -1 and multiplied by -10 = 10.
two prime numbers whose product is 141 = 3 & 47
There are no two primes whose product is 50.There are no two primes whose product is 50.There are no two primes whose product is 50.There are no two primes whose product is 50.
1.61013 and 17.38987 (approx).
Three and Seven
59
There are no real numbers that satisfy the requirements. The complex solutions are: 1 +/- sqrt(21)
two prime numbers whose product is 141 = 3 & 47
Any two numbers whose product is '1' are each others' reciprocals.
There are no two primes whose product is 50.There are no two primes whose product is 50.There are no two primes whose product is 50.There are no two primes whose product is 50.
find two positive numbers whose product is a maximum. 1.) the sum is s.
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
-76 and 76 whose product is -5776.
19
11
asked to work out the product of two or more numbers, then you need to multiply the numbers together. If you are asked to find the sum of two or more numbers, then you need to add the numbers together.
67
There are no such numbers.