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When the smaller of two consecutive integers is added to two times the larger the result is 26 find the integers?
Let x represent the smaller of the two integers.
Since integers are also members of the set of whole numbers, then the next largest consecutive integer must be (x+1)
Translating the question into a mathematical equation:
x + 2(x + 1) = 26
x + 2x + 2 = 26
add the "ex's"
3x + 2 = 26
subtract 2 from both sides of the equation
3x = 24
divide both sides of the equation by 3, to solve for x
x = 8, and x + 1 = 9
the solution is 8 and 9 [8 + (2*9)] = 26;; [8 + 18] = 26
What else can I help you with?
When the smaller of two consecutive integers is added to two times the larger the result is 17 find the integers?
They are 5 and 6 because 5+(2*6) = 17
When the smaller of two consecutive integers is added to four times the larger the result is 59?
Let the smaller be n, then the larger is n+1; and: n + 4(n+1) = 59 → n + 4n + 4 = 59 → 5n = 55 → n = 11 → the two consecutive integers are 11 and 12.
When the smaller of two consecutive integers is added to five times the larger the result is 41?
Suppose n is the smaller integer. Then the larger integer is n + 1, so that 5 times the larger is 5*(n + 1). Their sum is n + 5*(n + 1) = 6n + 5 Therefore 6n + 5 = 41 6n = 41 - 5 = 36 So that n = 36/6 = 6
What are two consecutive integers of 132?
The question refers to two factors of 132 that are consecutive integers. The answer is 11 & 12, as 11 x 12 = 132 This can be solved as follows. Let n be the smaller of the two numbers then (n + 1) is the other number. n(n + 1) = 132 n2 + n = 132 n2 + n - 132 = 0............which can be factored as (n + 12 )(n - 11) = 0 As we are only concerned with the positive integer result then this occurs when n - 11 = 0, that is when n = 11, thus (n + 1) = 12. NOTE : Integers can also be negative and this applies to the other solution when n + 12 = 0, so n = -12 and consequently (n + 1) = -11 giving the result that -12 x -11 = 132.
What is a quotient of integers?
A quotient of integers is the result of dividing one integer by another. When dividing two integers, the result may be a whole number if the division is exact, or a decimal/fraction if there is a remainder. For example, when dividing 10 by 2, the quotient is 5, which is also an integer.
When the smaller of two consecutive integers is added to three times the larger the result is 51. Find the integers?
12 and 13.
When the smaller of two consecutive integers is added to five times the larger the result is 65?
The integers are 10 and 11.
When the smaller of two consecutive integers is added to two times the larger the result is 17 find the integers?
They are 5 and 6 because 5+(2*6) = 17
When the smaller of two consecutive integers is added to four times the larger the result is 59?
Let the smaller be n, then the larger is n+1; and: n + 4(n+1) = 59 → n + 4n + 4 = 59 → 5n = 55 → n = 11 → the two consecutive integers are 11 and 12.
When the smaller of two consecutive integers is added to five times the larger the result is 53. Find the integers?
6x + 5 = 53 6x = 48 x = 8 8 + 45 = 53 8 and 9
What are two consecutive odd integers that when twice the larger is added to the small the result is 169?
55 and 57
When the smaller of two integers is added to three times the larger the result is 51. Find the integers?
12 and 13.
When the smaller of two consecutive integers is added to five times the larger the result is 53 find the integers?
x+5(x+1)=53 6x+5=53 6x=48 x=8 numbers=8 and 9
Can you answer 4 consecutive integers result is 24?
There is not such set of integers.
When the smaller of two consecutive integers is added to three times the larger the result is 43 find the integers?
Suppose the smaller integer is x, then the larger one is x+1. x + 3*(x+1) = 43 That is x + 3x + 3 = 43 so that 4x = 40 and that implies that x = 10 and so the other integer is 11.
When the smaller of the two consecutive integers is added to three times the larger the result is 47 Find the integers?
Let the integers be n and n + 1.n + 3(n+ 1) = 47 4n + 3 = 47 4n = 44 n = 11 n+ 1 = 12.
When the smaller of two consecutive integers is added to three times the larger result is 23?
this is a algebraic word problem: we know we have two consecutive integers so x + 1 = y and we know that the smaller one (x) added to three times the larger, the results is 23 so x + 3y = 23 substitute (x+1) for y: x + 3(x+1) = 23 4x + 3 = 23 4x = 20 x = 5 y = 6
