457
1111
In binary: 1111 1111 1111 1111 1111 1111 1111 1111 In octal: 37777777777 In hexadecimal: FFFFFFFF in decimal: 2³² - 1 = 4,294,967,295
The factors of 1111 are: 1, 11, 101, 1111.
10% of 1111 pound = 1111*10/100 = 111.1 pounds
Alright, let's forget the - for a while convert 5 to binary. do this: 5/2=2.5 2/2=1 1/2=0,5 than this: 2.5 absolute value=2 1 absolute value=1 0,5 absolute value=0 finally this 2*2=4 and 5-4=1 2*1=2 and 2-2=0 2*0=0 and 1-0=1 <--(last digit) = 101 complete the binary number by placing a 0= 0101. Now as you might know HW = 2 bytes and 1 byte is 8 bits so to to complete you should place 0000 0000 0000 before your result: 0000 0000 0000 0101 Let's not forget about the - though... you'll have to invert your result 0000 0000 0000 0101= 1111 1111 1111 1010 and increment it by 1=1111 1111 1111 1011 and there is your result... You could check your result this way: 0000 0000 0000 0101 +1111 1111 1111 1011 1 0000 0000 0000 0000 The first bit defines if your decimal has a + or - (1=- and 0=+) The rest is simple... (1111=F) (1111=F) (1111=F) (1011=B)=FFFB (hex HW)
111111 in binary is 255 in decimal which is FF in hexadecimal (i.e. 15 units and 15 16s)
1111
In binary: 1111 1111 1111 1111 1111 1111 1111 1111 In octal: 37777777777 In hexadecimal: FFFFFFFF in decimal: 2³² - 1 = 4,294,967,295
That looks like hexadecimal. Convert each hex digit to 4 binary digits: B = 1011, 2 = 0010, F = 1111, so the final result is 1011 0010 1111.That looks like hexadecimal. Convert each hex digit to 4 binary digits: B = 1011, 2 = 0010, F = 1111, so the final result is 1011 0010 1111.That looks like hexadecimal. Convert each hex digit to 4 binary digits: B = 1011, 2 = 0010, F = 1111, so the final result is 1011 0010 1111.That looks like hexadecimal. Convert each hex digit to 4 binary digits: B = 1011, 2 = 0010, F = 1111, so the final result is 1011 0010 1111.
The way I convert between decimal and hexadecimal is to first convert the decimal number to binary: 664062510 = 110010101010011111100012 Then split the binary number into 16-bit (4 digit) chunks: 0110 0101 0101 0011 1111 00012 Next, convert each chunk into a hexadecimal digit: 0110 0101 0101 0011 1111 00012 6 5 5 3 F 1 Finally, put all the digits together: 664062510 = 6553F116
Yes, a byte is 8 bits, and a one hexadecimal digit takes up four bits, so two hexadecimal digits can be stored in a byte. The largest hexadecimal digit is F (which is 15 in base ten.) In base two, this converts to 1111, which takes up four bits, which is why it only takes four bits to store a hexadecimal digit. With 8 bits, two hexadecimal digits can be stored (FF would be 11111111, which is 8 bits), and 8 bits make up a byte. Generally, 4 bits are always used to store a hexadecimal digit, using leading zeros where necessary. For example, the hexadecimal digit 5 would be stored as 0101, and the hexadecimal digits 5A would be stored as 01011010.
1 + 1,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111 = 1,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,112 Unless it is binary, in which case: 1 + 111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 11111 1111 1111 1111 1111 = 1000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000
16 is the 4th power of 2. So a hexadecimal number is converted to binary by replacing each hex digit by the 4-bit binary number having the same value. Conversely, in converting binary to hexadecimal, we group every 4 bits starting at the decimal (binary?) point and replace it with the equivalent hex digit. For example, the hexadecimal number 3F9 in binary is 1111111001, because 3 in binary is 11, F (decimal 15) is 1111, and 9 is 1001.
0xc = 1100 Hexadecimal digits use exactly 4 binary digits (bits). The 0x0 to 0xf of hexadecimal map to 0000 to 1111 of binary. Thinking of the hexadecimal digits as decimal numbers, ie 0x0 to 0x9 are 0 to 9 and 0xa to 0xf are 10 to 15, helps with the conversion to binary: 0xc is 12 decimal which is 8 + 4 → 1100 in [4 bit] binary.
39% of 1111= 39% * 1111= 0.39 * 1111= 433.29
Hexadecimal means 16. So that 4 binary bits are represented by a hexadecimal number. 0000 = 0 1000 = 8 0001 = 1 1001 = 9 0010 = 2 1010 = A 0011 = 3 1011 = B 0100 = 4 1100 = C 0101 = 5 1101 = D 0110 = 6 1110 = E 0111 = 7 1111 = F
The factors of 1111 are: 1, 11, 101, 1111.