2x2-3x-5 = (2x-5)(x+1) when factored
(2x + 7)(x - 2)
You would first factor out anything that is common between the 3 parts. 2x2 is the greatest common factor. To pull out the 2x2, you divide each term by 2x2 like so:12x4/2x2=6x210x3/2x2=5x-12x2/2x2=-6We now know that 12x4+10x3-12x2= 2x2(6x2+5x-6)The next step involves using the "slip and slide" method for the trinomial inside the parentheses:6x2+5x-6x2+5x-36(x+9)(x-4)(x+9/6)(x-4/6)(x+3/2)(x-2/3)(2x+3)(3x-2)Remembering that the result for the slip and slide method only accounts for 6x2+5x-6 we must multiply (2x+3)(3x-2) by 2x2.Your final answer is 2x2(2x+3)(3x-2).
It is: 3(x-5)
8x2-3x-5 = (8x+5)(x-1) when factored
2x2-3x-5 = (2x-5)(x+1) when factored
(x + 1)(2x - 5)
2(x^2 - 3x - 5)
2x2 equals 5
2x2 - 3x-5
(x + 1) / (2x3 + 3x + 5) --- Can't depict long division here, but you can work this out by seeing if (x + 1) is a factor of (2x3 + 3x + 5). If it is, then the answer will be 1/(the other factor). In this case, that is true. (2x3 + 3x + 5)/(x + 1) = 2x2 - 2x + 5, so the term term above is equal to: 1 / (2x2 - 2x + 5)
2x2-4x-3x+6 2x2-7x+6 (2x+3)(x+2)
-11
2X2 = 3Xset to 02X2 - 3X = 0factorX(2X - 3) = 0zero factor rule2X = 3 = 02X = 3X = 3/2======X = 0X = 3/2
(x-2)(2x+7)
2x2 + 3x - 20 = (x + 4)(2x - 5).
(2x + 7)(x - 2)