2(x^2 - 3x - 5)
2x2-x-6 = (2x+3)(x-2)
the prime factorization of 32 is 2x2x2x2x2 and the factor tree is 32 8 4 2x4 2x2 2x2
4x4 + 1 = (2x2 - 2x + 1)(2x2 + 2x + 1)
2x2+13x+15 = (2x+3)(x+5)
2X2+5x-12 4+5x-12 -8+5x 5x-8
Show the terms as additive here..., 8X2 + 10X3 factor out 2X2 2X2(4 + 5X) ---------------- 2X2 ==== greatest common factor
(2x2 - 1)(2x2 - 1) or (2x2 - 1)2
2x2 (i.e. 4)
2x^(2) - 5x - 12 First write down all the factors of '2' & '12' 2 = 1,2 12 = 1,12; 2,6; 3,4 . From this we select two pairs of numbers, one pair from each coefficient, that add/multiply to '5' They are, 1,2 & 3,4 Hence -(2 x 4) + (1 x 3) = -8 + 3 = -5 Set up the brackets (2x 3)(x 4) Hence the signs are ( 2x + 3)(x - 4)
Assuming you mean 2x2 -127 x -4896: trying to factor using integers. This is PRIME.
2x2-x-6 = (2x+3)(x-2)
2x2 - 13x - 7 = (2x + 1)(x - 7)
2x2- 2x = 2x*(x - 1)
the prime factorization of 32 is 2x2x2x2x2 and the factor tree is 32 8 4 2x4 2x2 2x2
4x4 + 1 = (2x2 - 2x + 1)(2x2 + 2x + 1)
2x2+13x+15 = (2x+3)(x+5)
2x2-3x-5 = (2x-5)(x+1) when factored